jQuery名望的John Resig提供了Simple JavaScript Inheritance的简洁实现。他的方法激发了我进一步改进工作的尝试。我已经重写了Resig的原始Class.extend
函数,以包括以下优点:
因为这似乎太真实了,所以我想确保我的逻辑没有任何基本的缺陷或错误,并查看是否有人可以提出改进建议或反驳代码。这样,我介绍了
classify
函数:function classify(base, properties)
{
/// <summary>Creates a type (i.e. class) that supports prototype-chaining (i.e. inheritance).</summary>
/// <param name="base" type="Function" optional="true">The base class to extend.</param>
/// <param name="properties" type="Object" optional="true">The properties of the class, including its constructor and members.</param>
/// <returns type="Function">The class.</returns>
// quick-and-dirty method overloading
properties = (typeof(base) === "object") ? base : properties || {};
base = (typeof(base) === "function") ? base : Object;
var basePrototype = base.prototype;
var derivedPrototype;
if (Object.create)
{
// allow newer browsers to leverage ECMAScript 5 features
var propertyNames = Object.getOwnPropertyNames(properties);
var propertyDescriptors = {};
for (var i = 0, p; p = propertyNames[i]; i++)
propertyDescriptors[p] = Object.getOwnPropertyDescriptor(properties, p);
derivedPrototype = Object.create(basePrototype, propertyDescriptors);
}
else
{
// provide "shim" for older browsers
var baseType = function() {};
baseType.prototype = basePrototype;
derivedPrototype = new baseType;
// add enumerable properties
for (var p in properties)
if (properties.hasOwnProperty(p))
derivedPrototype[p] = properties[p];
// add non-enumerable properties (see https://developer.mozilla.org/en/ECMAScript_DontEnum_attribute)
if (!{ constructor: true }.propertyIsEnumerable("constructor"))
for (var i = 0, a = [ "constructor", "hasOwnProperty", "isPrototypeOf", "propertyIsEnumerable", "toLocaleString", "toString", "valueOf" ], p; p = a[i]; i++)
if (properties.hasOwnProperty(p))
derivedPrototype[p] = properties[p];
}
// build the class
var derived = properties.hasOwnProperty("constructor") ? properties.constructor : function() { base.apply(this, arguments); };
derived.prototype = derivedPrototype;
derived.prototype.constructor = derived;
derived.prototype.base = derived.base = basePrototype;
return derived;
}
除了构造函数名称(
constructor
与init
)以及基类方法调用的语法外,用法与Resig几乎相同。/* Example 1: Define a minimal class */
var Minimal = classify();
/* Example 2a: Define a "plain old" class (without using the classify function) */
var Class = function()
{
this.name = "John";
};
Class.prototype.count = function()
{
return this.name + ": One. Two. Three.";
};
/* Example 2b: Define a derived class that extends a "plain old" base class */
var SpanishClass = classify(Class,
{
constructor: function()
{
this.name = "Juan";
},
count: function()
{
return this.name + ": Uno. Dos. Tres.";
}
});
/* Example 3: Define a Person class that extends Object by default */
var Person = classify(
{
constructor: function(name, isQuiet)
{
this.name = name;
this.isQuiet = isQuiet;
},
canSing: function()
{
return !this.isQuiet;
},
sing: function()
{
return this.canSing() ? "Figaro!" : "Shh!";
},
toString: function()
{
return "Hello, " + this.name + "!";
}
});
/* Example 4: Define a Ninja class that extends Person */
var Ninja = classify(Person,
{
constructor: function(name, skillLevel)
{
Ninja.base.constructor.call(this, name, true);
this.skillLevel = skillLevel;
},
canSing: function()
{
return Ninja.base.canSing.call(this) || this.skillLevel > 200;
},
attack: function()
{
return "Chop!";
}
});
/* Example 4: Define an ExtremeNinja class that extends Ninja that extends Person */
var ExtremeNinja = classify(Ninja,
{
attack: function()
{
return "Chop! Chop!";
},
backflip: function()
{
this.skillLevel++;
return "Woosh!";
}
});
var m = new Minimal();
var c = new Class();
var s = new SpanishClass();
var p = new Person("Mary", false);
var n = new Ninja("John", 100);
var e = new ExtremeNinja("World", 200);
这是我所有通过的QUnit测试:
equals(m instanceof Object && m instanceof Minimal && m.constructor === Minimal, true);
equals(c instanceof Object && c instanceof Class && c.constructor === Class, true);
equals(s instanceof Object && s instanceof Class && s instanceof SpanishClass && s.constructor === SpanishClass, true);
equals(p instanceof Object && p instanceof Person && p.constructor === Person, true);
equals(n instanceof Object && n instanceof Person && n instanceof Ninja && n.constructor === Ninja, true);
equals(e instanceof Object && e instanceof Person && e instanceof Ninja && e instanceof ExtremeNinja && e.constructor === ExtremeNinja, true);
equals(c.count(), "John: One. Two. Three.");
equals(s.count(), "Juan: Uno. Dos. Tres.");
equals(p.isQuiet, false);
equals(p.canSing(), true);
equals(p.sing(), "Figaro!");
equals(n.isQuiet, true);
equals(n.skillLevel, 100);
equals(n.canSing(), false);
equals(n.sing(), "Shh!");
equals(n.attack(), "Chop!");
equals(e.isQuiet, true);
equals(e.skillLevel, 200);
equals(e.canSing(), false);
equals(e.sing(), "Shh!");
equals(e.attack(), "Chop! Chop!");
equals(e.backflip(), "Woosh!");
equals(e.skillLevel, 201);
equals(e.canSing(), true);
equals(e.sing(), "Figaro!");
equals(e.toString(), "Hello, World!");
与John Resig的original approach相比,有人对我的方法有什么看法吗?欢迎提出建议和反馈!
注意:自从我最初发布此问题以来,以上代码已被重大修改。以上是最新版本。要查看其发展情况,请查看修订历史记录。
最佳答案
前一段时间,我查看了JS的多个对象系统,甚至实现了自己的一些对象系统,例如class.js(ES5 version)和proto.js。
我从未使用过它们的原因:您最终将编写相同数量的代码。恰当的例子:Resig的Ninja示例(仅添加了一些空白):
var Person = Class.extend({
init: function(isDancing) {
this.dancing = isDancing;
},
dance: function() {
return this.dancing;
}
});
var Ninja = Person.extend({
init: function() {
this._super(false);
},
swingSword: function() {
return true;
}
});
19行,264字节。
具有
Object.create()
的标准JS(这是ECMAScript 5函数,但是出于我们的目的,可以用自定义ES3 clone()
实现代替):function Person(isDancing) {
this.dancing = isDancing;
}
Person.prototype.dance = function() {
return this.dancing;
};
function Ninja() {
Person.call(this, false);
}
Ninja.prototype = Object.create(Person.prototype);
Ninja.prototype.swingSword = function() {
return true;
};
17行,282字节。另外,额外的字节并不能解决单独对象系统增加的复杂性。通过添加一些自定义函数来简化标准示例很容易,但是再次:这样做确实不值得。
关于javascript - 改善简单的JavaScript继承,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/2510342/