关于相同有几篇文章,但是我仍然无法使我期望的脚本正常工作。我的意图是使所有操作自动化,但保留用户输入的密码。因此,脚本包含3部分:

  • 自动登录
  • 给用户交互输入密码
  • 将控制权交还给Expect脚本以继续工作

  • 所以我有将要生成的脚本,并且具有3个读取命令。第一个和最后一个应该由Expect填写,第二个我要输入我自己:
    #!/bin/ksh
    read user?User:
    echo "Expect entered the username $user"
    read pass?Password:
    echo "User entered the password $pass"
    read command?"Shell>"
    echo "Expect entered the command $command"
    

    我的期望脚本:
    #!/usr/bin/expect
    spawn ./some_script
    expect User
    send I-am-expect\r
    expect Password
    interact
    expect Shell
    send I-am-expect-again
    

    不幸的是,在我输入密码后,脚本无法继续运行,并处于交互模式:
    [root@localhost ~]# ./my-expect
    spawn ./some_script
    User:I-am-expect
    Expect entered the username I-am-expect
    Password:i am user
    User entered the password i am user
    Shell>
    

    最后,当我在“Shell”上输入内容并按[ENTER]时,期望退出并显示以下错误:
    Expect entered the command
    expect: spawn id exp4 not open
        while executing
    "expect Shell"
        (file "./my-expect" line 7)
    [root@localhost ~]#
    

    我希望对此问题做出任何解释或解决。我正在使用期望版本5.45

    最佳答案

    您可以自己读取(expect_user)用户密码,然后将send密码生成到生成的程序中。例如:

    [STEP 101] # cat foo.exp
    proc expect_prompt {} \
    {
        global spawn_id
        expect -re {bash-[.0-9]+(#|\$)}
    }
    
    spawn ssh -t 127.0.0.1 bash --noprofile --norc
    expect "password: "
    
    stty -echo
    expect_user -timeout 3600 -re "(.*)\[\r\n]"
    stty echo
    send "$expect_out(1,string)\r"
    
    expect_prompt
    send "exit\r"
    expect eof
    [STEP 102] # expect foo.exp
    spawn ssh -t 127.0.0.1 bash --noprofile --norc
    [email protected]'s password:
    bash-4.3# exit
    exit
    Connection to 127.0.0.1 closed.
    [STEP 103] #
    

    关于linux - 期待,互动,然后再次期待,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/33854568/

    10-09 16:53