我正在做一个“史蒂夫·赖希-拍手音乐”,用“ xoxoxoxx”作为拍手。但我希望它在继续向右移动的同时写模式。所以你会有这样的写法:
xoxoxoxxxoxoxoxxxoxoxoxxxoxoxoxx
xoxoxoxxoxoxoxoxxxoxoxxoxoxxxoxoxo
因此它会打印X或O,然后向右移一点并再次打印。我希望这很清楚,英语不是我的母语,所以如果很难理解,我感到抱歉。这是两行的完整代码,因为我不好解释:
var noise, env;
var seq = "o x o x o x o x o x o x o x x x";
var steps = seq.split(" ");
var speed = 8;
var count = 0;
var count2 = 0;
var count3=0;
var shift = 0;
var repeat = 1;
var sf, sf2, sf3;
var f;
function preload() {
sf = loadSound("./files/clap.wav");
sf2 = sf;
sf3 = sf;
}
function setup() {
createCanvas(400, 400);
env = new p5.Env(0.01, 1, 0.2, 0.1);
env2 = new p5.Env(0.1, 0.8, 0.01, 0.1);
env3 = new p5.Env(0.05, 0.9, 0.1, 0.1);
}
function hitMeSteve(when, env, loc) {
if (when == 'x' && frameCount % speed == 0) {
env.play();
}
}
function draw() {
if (frameCount % speed == 0) {
count++;
}
if (frameCount % (steps.length * speed * repeat) == 0) {
shift++;
count2=count2+2;
count3=count3+4;
}
if(shift==4){
shift=0;
count2=0;
count3=0;
}
shift = shift % steps.length;
shift2 = shift + 2;
var now = steps[count % steps.length];
hitMeSteve(now, sf, 10);
var canon = steps[(count + shift) % steps.length];
hitMeSteve(canon, sf2, width / 2 + 10);
var canon2 = steps[(count + shift+count2) % steps.length];
hitMeSteve(canon2, sf3, width / 2 + 20);
textSize(30);
//1
for (var i = 0; i < steps.length; i++) {
if (i == count % steps.length) {
fill(255, 180, 0);
} else {
fill(0);
}
text(steps[i],10+ ( + i) * 15,20);
//text(steps[i], 110 + (shift / 2 + i) * 15, height / 2);
}
//2
for (var i = 0; i < steps.length; i++) {
if (i == (count + shift) % steps.length) {
fill(255, 180, 0);
} else {
fill(0);
}
text(steps[i],10+( + i)*15,40);
//text(steps[i], 110 + (-shift / 2 + i) * 15, height / 2 + 20);
}
}
最佳答案
只是setInterval
的建议,也许对您有用。
var content = "oxoxoxoxoxoxoxxx",
target = document.getElementById('ticker'),
i = 0,
timer = setInterval(addChar, 800);
function addChar() {
if (i < content.length) {
target.innerHTML += ' ' + content[i];
i++;
} else {
target.innerHTML = '';
i=0;
}
}
<div id="ticker"></div>
关于javascript - 用JavaScript编写模式,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/36131836/