c - 为什么我的wc实现一言不发？

[已解决]编写解析代码是一个陷阱。一行15个空格将有15个单词。空行也算作单词。回到flex和bison。

#include        <stdio.h>
#include        <stdlib.h>

int     main(int argc, char     *argv[]) {

        FILE    *fp = NULL;
        int             iChars =0, iWords =0, iLines =0;
        int             ch;

        /* if there is a command line arg, then try to open it as the file
                otherwise, use stdin */

        fp = stdin;
        if (argc == 2) {
                fp = fopen(argv[1],"r");
                if (fp == NULL) {
                        fprintf(stderr,"Unable to open file %s. Exiting.\n",argv[1]);
                        exit(1);
                }
        }

        /* read until the end of file, counting chars, words, lines */
        while ((ch = fgetc(fp)) != EOF) {
                if (ch == '\n') {
                        iWords++;
                        iLines++;
                }

                if (ch == '\t' || ch == ' ') {
                        iWords++;
                }

                iChars++;
        }

        /* all done. If the input file was not stdin, close it*/
        if (fp != stdin) {
                fclose(fp);
        }

        printf("chars: %d,\twords: %d,\tlines: %d.\n",iChars,iWords,iLines);
}

测试数据foo.sh

#!/home/ojblass/source/bashcrypt/a.out
This is line 1
This is line 2
This is line 3

ojblass@linux rjxl:~/source/bashcrypt>
世界杯足球赛
51385福斯
ojblass@linux rjxl:~/source/bashcrypt>
外卖
字符：85，单词：14，行：5。

最佳答案

即使是空行，您也可以将其作为一个字来计算。

关于c - 为什么我的wc实现一言不发？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/739596/