c++ - 在main中使用函数的局部变量

我尝试搜索遮阳篷，但是所有线程都是不同的lang。

#include <cstdlib>
#include <iostream>
#include <math.h>
using namespace std;

void calcDistance (int x1, int y1, int x2, int y2);

int main()
{
    int x1, y1, x2, y2;
    cout << "Enter the points in coordinate pair form, ommiting parantheses" << endl;
    cin >> x1 >> y1 >> x2 >> y2;

    calcDistance (x1,  y1,  x2,  y2);

    system("pause");
    // how do I cout the dist in main-- says dist isn't declared

}


void calcDistance (int x1, int y1, int x2, int y2)
{
    int sideA;
    sideA = x2 - x1;

    int sideB;
    sideB = y2 -y1;

    int sideAsqd;
    sideAsqd = sideA * sideA;

    int sideBsqd;
    sideBsqd = sideB * sideB;

    int sideCsqd;
    sideCsqd = sideAsqd + sideBsqd;

    double dist;
    dist = sqrt(sideCsqd);

    cout << "The calculated distance is "<< dist << endl;

}

我如何使第二次发生在main中。我尝试仅将其放在main中，但是随后出现一个错误，提示dist未在范围中声明。

我希望能够在main中使用dist值，而该值已在函数中计算出来。

最佳答案

更改您的功能：

double calcDistance (int x1, int y1, int x2, int y2)
{
    int sideA = x2 - x1;

    int sideB = y2 -y1;

    int sideAsqd = sideA * sideA;

    int sideBsqd = sideB * sideB;

    int sideCsqd = sideAsqd + sideBsqd;

    double dist = sqrt(sideCsqd);

    return dist;
}

并主要这样做：

double res =  calcDistance (x1,  y1,  x2,  y2);
cout << "The calculated distance is "<< res << endl;

关于c++ - 在main中使用函数的局部变量，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/19245995/