我已经制作了这个程序来计算数字分解,例如60 = 2^2 * 5 * 3
。
如何在不使用math.h库且不使用数组的情况下修改代码以打印9000 = 2^3 * 3^2 * 5^3
之类的POWERFUL NUMBERS?
非常感谢你!!
#include<stdio.h>
#define MAX 1000
int main(){
int num;
int counter;
int number;
char factorizationOutput;
int isAchiles = 0;
int factor=2;
for(counter=2;counter<=MAX;counter++){
isAchiles = 1;
number=counter;
int factor=2;
while(factor<number){
int power=0;
if(number%factor==0){
while(number%factor==0){
number=number/factor;
power++;
}
if(power == 1){
isAchiles = 0;
}
printf("%d^%d",factor,power);
if(number!=1)
printf(" X ");
}
factor++;
}
if(number!=1)
printf("%d^1.\n",factor);
if(isAchiles == 1){
printf("factorazation of number %d is: ",counter);
}
}
}
最佳答案
#include<stdio.h>
int main(void)
{
int n;
scanf("%d", &n);
printf("%d = ", n);
for(int i = 1; i <= n; i++)
{
int count = 0;
for(int j = 1; j <= i; j++)
{
if(i % j == 0)
{
count++;
}
}
int l = 0;
if(count == 2)
{
while(n % i == 0)
{
l++;
n = n/i;
}
printf("%d^%d*", i, l);
}
}
}
关于c - 在哪里放置强数声明?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/59092037/