我想在我的项目senior writer
和junior writer
中获得像徽章这样的声誉。基于获得的总数的用户信誉。
我有3张桌子:
表格发布:
id_post | news | id_user
3 | IT news | 1
4 | game news | 2
表用户:
id_user | username
1 | dora
2 | boots
3 | swipper
票数:
id_vote | id_post | id_user | LIKE
10 | 3 | 2 | 1
11 | 3 | 1 | 1
12 | 4 | 3 | 1
这是我的查询:
SELECT p.*, SUM(like) AS like_post,
(SELECT SUM(like) //this is subquery start
FROM user u
LEFT JOIN post p ON p.id_user= u.id_user
LEFT JOIN vote v ON v.id_post=p.id_post GROUP BY u.id) AS reputation // end subquery
FROM post p
LEFT join user u ON p.id_user=u.id_user
LEFT JOIN vote v ON p.id_post=v.id_post
GROUP BY p.id_post
ORDER BY p.id_post DESC
LIMIT 10;
这是我的看法:
<?php foreach $news as $data:?>
<?php echo $data['id_post'];?>
<?php echo $data['title'];?>
LIKE: <?php echo $data['like_post']; ?>
post by <?php echo $data['username'];?>
reputation: <?php if ($data['reputation']==1)
{echo "JUNIOR writer";}
else
{echo "SENIOR Writer"; }
?>
<?php endforeach;?>
我的期望用户Dora因为获得2个LIKE而将获得名为
senior writer
的声誉。靴子将获得称为junior writer
的声誉,因为仅获得1赞。问题是返回查询是这样的错误:
Subquery returns more than 1 row
有答案吗?
非常感谢...
最佳答案
使用此查询。
SELECT u.id_user, u.username, SUM(v.like) AS reputation
FROM user u
LEFT JOIN post p ON u.id_user=p.id_user
LEFT JOIN vote v ON v.id_post=p.id_post
GROUP BY u.id_user
使用此php代码。
LIKE: <?php echo $data['reputation']; ?>
post by <?php echo $data['username'];?>
reputation: <?php if ($data['reputation']==1)
{echo "JUNIOR writer";}
else
{echo "SENIOR Writer"; }
?>
<?php endforeach;?>
编辑:**
查询
like_post
SELECT v.id_user,v.id_post,SUM(v.like1) AS like_post
FROM vote v
LEFT JOIN USER u ON v.id_user=u.id_user
GROUP BY u.id_user
查询
reputation
SELECT u.id_user, u.username, SUM(v.like1) AS reputation
FROM USER u
LEFT JOIN post n ON u.id_user=n.id_user
LEFT JOIN vote v ON v.id_post=n.id_post
GROUP BY u.id_user
关于php - 如何显示用户声誉,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/27982257/