#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void encrypting(char cipher[25], int shift, int num)
{
int i;
for (i = 0; i < num; i++)
{
if (cipher[i] >= 'A' && cipher[i] <= 'Z')
{
cipher[i] = (char)(((cipher[i] + shift - 'A' + 26) % 26) + 'A');
}
else if (cipher[i] >= 'a' && cipher[i] <= 'z')
{
cipher[i] = (char)(((cipher[i] + shift - 'a' + 26) % 26) + 'a');
}
}
}
void decrypting(char cipher[25], int shift, int num)
{
inti;
for (i = 0; i < num; i++)
{
if (cipher[i] >= 'A' && cipher[i] <= 'Z')
{
cipher[i] = (char)(((cipher[i] - shift - 'A' + 26) % 26) + 'A');
}
else if (cipher[i] >= 'a' && cipher[i] <= 'z')
{
cipher[i] = (char)(((cipher[i] - shift - 'a' + 26) % 26) + 'a');
}
}
}
int main()
{
char text[10];
static const char encrypt[] = "2";
static const char decrypt[] = "1";
int shift;
char cipher[25];
int result1;
int result2;
int num;
int i;
printf("Enter operation: encrypt or decrypt/n");
printf("Press 1 to Encrypt or 2 to Decrypt");
scanf("%c", &text);
printf("Enter shift key");
scanf("%d", &shift);
printf("Enter text to encrypt/decrypt");
fflush(stdin);
scanf("%c", &cipher);
num = strlen(cipher);
result1 = strcmp(text, encrypt);
result2 = strcmp(text, decrypt);
if (result1 == 0)
{
decrypting(cipher, shift, num);
}
else { exit(0); }
if (result2 == 0)
{
encrypting(cipher, shift, num);
}
else { exit(0); }
printf("Result");
printf("%d", cipher);
}
用户输入密文后,程序意外终止。我不知道现在是什么问题。谁能立即解释我的代码有什么问题?感谢所有帮助。
最佳答案
因为无论用户是要加密还是解密,您都在exit(0);
之前先调用printf("Result");
。更改:
else{exit(0);}
if(result2 == 0)
至:
else if(result2 == 0)
然后,如果他们既未选择加密也未选择解密,则仅调用
exit(0);
。另外,
printf("%d",cipher);
将无法打印字符串。您需要使用%s
转换说明符而不是%d
。关于c - C程序意外终止,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/23333023/