c++11 - 在此范围内未声明C++ gettid()

一个简单的程序是：
我想使用此gettid函数获取两个线程的线程ID。我不想直接执行sysCall。我想使用这个功能。

#include <iostream>
#include <boost/thread/thread.hpp>
#include <boost/date_time/date.hpp>
#include <unistd.h>
#include <sys/types.h>
using namespace boost;
using namespace std;

boost::thread thread_obj;
boost::thread thread_obj1;

void func(void)
{
    char x;
    cout << "enter y to interrupt" << endl;
    cin >> x;
     pid_t tid = gettid();
    cout << "tid:" << tid << endl;
    if (x == 'y') {
        cout << "x = 'y'" << endl;
        cout << "thread interrupt" << endl;
    }
}

void real_main() {

   cout << "real main thread" << endl;
    pid_t tid = gettid();
    cout << "tid:" << tid << endl;

    boost::system_time const timeout = boost::get_system_time() + boost::posix_time::seconds(3);
    try {
        boost::this_thread::sleep(timeout);
    }
    catch (boost::thread_interrupted &) {
        cout << "thread interrupted" << endl;
    }

}

int main()
{
    thread_obj1 = boost::thread(&func);
    thread_obj = boost::thread(&real_main);
    thread_obj.join();
}

它在编译时给出错误； gettid（）的使用已根据手册页完成：

$g++ -std=c++11 -o Intrpt Interrupt.cpp -lboost_system -lboost_thread
Interrupt.cpp: In function ‘void func()’:
Interrupt.cpp:17:25: error: ‘gettid’ was not declared in this scope
      pid_t tid = gettid();

最佳答案

这是一个愚蠢的glibc错误。像这样解决它：

#include <unistd.h>
#include <sys/syscall.h>
#define gettid() syscall(SYS_gettid)

关于c++11 - 在此范围内未声明C++ gettid()，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/30680550/