android - 如何将图像转换为纹身？

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8年前关闭。




我正在使用纹身应用程序，因为我需要将图像(从相机拍摄或从图库中选择)转换为纹身...

我的要求如下

我从github找到了一个示例代码https://github.com/DrewDahlman/ImageFilter/tree/master/Android/project
它用于图像过滤..

我不知道将图像转换为纹身的过程是否正确

如果有人知道android中的这个纹身，请建议我，我在谷歌上搜索了很多

提前致谢..

最佳答案

你需要一个差异过滤器:

1)你计算水平差异(在这里你会有垂直段)

2)你计算垂直差异(这里是水平段)

3)你或两张 map ，找到轮廓

4) 重新创建一个 Bitmap 对象，如果你愿意的话

类似(已编辑):

int[] pixels;
int width = yourbitmap.getWidth();
int height = yourbitmap.getHeight();
yourbitmap.getPixels(pixels, 0, width, 0, 0, width, height);

// transform grayscale
int[] image = new int[width*height];
for (int y=0; y<height; y++)
    for (int x=0; x<width; x++)
    {
        int pixel = image[y*width + x];
        image[y*width + x] = (Color.red(pixel) + Color.green(pixel) + Color.blue(pixel))/3;
    }

// calculate diff_x (vertical segments)
int[] dx = new int[width*height];

for (int y=0; y<height; y++)
    for (int x=0; x<width; x++)
        dx[y*width + x] = (x==0 || y== 0 ? 0 : Math.abs(image[y*width + x] - image[y*width + x-1]));

// calculate diff_y (horizontal segments)
int[] dy = new int[width*height];

for (int y=0; y<height; y++)
    for (int x=0; x<width; x++)
        dy[y*width + x] = (x==0 || y== 0 ? 0 : Math.abs(image[y*width+x] - image[(y-1)*width+x]));


// when the color intensity is higher than THRESHOLD, accept segment
// you'll want a slider to change THRESHOLD values
bool[] result = new bool[width*height];
const int THRESHOLD = 60; // adjust this value

for (int y=0; y<height; y++)
    for (int x=0; x<width; x++)
        result[y*width + x] = (dx[y*width + x] > THRESHOLD || dy[y*width + x] > THRESHOLD);

Bitmap result = Bitmap.createBitmap(width, height, Bitmap.Config.ARGB_8888);
for (int y=0; y<height; y++)
    for (int x=0; x<width; x++)
               result.setPixel(x, y, result[y*width+x]? Color.Black : Color.White);

关于android - 如何将图像转换为纹身？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/15610609/