@JsonDeserialize注释不起作用时,我遇到了问题。例如,当来自客户端的生日值包含“ 12.06.1999”时,我得到了400 Bad Request http代码响应。
对我来说,这是一个非常奇怪的行为,因为@JsonSerialize注释可以很好地工作!但是,如果我使用@DateTimeFormat注释而不是@JsonDeserialize,那么所有方法都可以使用。

我使用Java 8,有我的代码:

public class Person {
    @JsonProperty("birthday")
    @JsonSerialize(using = DateSerializer.class)
    @JsonDeserialize(using = DateDeserializer.class)
    private LocalDate birthday;

    // other fields, getter and setter, etc.
}

public class DateSerializer extends JsonSerializer<LocalDate> {
    private static final DateTimeFormatter formatter = DateTimeFormatter.ofPattern("dd.MM.yyyy");

    @Override
    public void serialize(LocalDate value, JsonGenerator generator, SerializerProvider provider)
        throws IOException, JsonProcessingException {
        generator.writeString(formatter.format(value));
    }
}

public class DateDeserializer extends JsonDeserializer<LocalDate>{

    @Override
    public LocalDate deserialize(JsonParser jp, DeserializationContext ctxt)
            throws IOException, JsonProcessingException {

        ObjectCodec oc = jp.getCodec();
        TextNode node = oc.readTree(jp);
        String dateString = node.textValue();

        Instant instant = Instant.parse(dateString);
        LocalDateTime dateTime = LocalDateTime.ofInstant(instant, ZoneId.systemDefault());
        LocalDate date = LocalDate.of(dateTime.getYear(), dateTime.getMonth(), dateTime.getDayOfMonth());

        return date;
    }
}

@RequestMapping(value = "/savePerson", method = RequestMethod.POST)
@ResponseBody
public Map<String, Object> savePerson(@ModelAttribute("person") Person person)
{
    // a some code to save entity
}


我应该如何使用@JsonDeserialize

最佳答案

这可以满足您的目的:

public class Person {
    @JsonProperty("birthday")
    @JsonFormat(shape = JsonFormat.Shape.STRING, pattern="MM.dd.yyyy")
    private LocalDate birthday;

    // other fields, getter and setter, etc.
}

关于java - @JsonDeserialize注释不起作用,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/36633405/

10-09 03:51