我有以下代码:
Scalar m; //Scalar is a class for a 4 variable vector. m is its instance.
Scalar std;
meanStdDev(hist, m, std);
它运作良好,但不适用于以下情况。
vector < float > m;
vector < float > std;
meanStdDev(hist, m, std);
我无法理解问题,因为在这里我也像在Scalar中一样创建 vector 。请解释。
最佳答案
这里有2个问题:
1)它需要固定大小的东西。
2)您的 vector 最初是空的
您可以使用标量,(预先分配的)Mat或Vec4d,但不能使用std::vector。
Mat hist(10,1,CV_32F);
randu(hist,1,100);
cerr << hist << endl;
{
Scalar m, stdv;
meanStdDev(hist, m, stdv);
cerr << m << " " << stdv << endl;
}
{
Mat m(1,4,CV_64F),stdv(1,4,CV_64F);
meanStdDev(hist, m, stdv);
cerr << m << " " << stdv << endl;
}
{
Vec4d m,stdv;
meanStdDev(hist, m, stdv);
cerr << m << " " << stdv << endl;
}
[53.497997;
20.72666;
40.704884;
81.624123;
44.276165;
25.63018;
77.537399;
76.447281;
31.471653;
70.540741]
[52.2457, 0, 0, 0] [21.8056, 0, 0, 0]
[52.245703125] [21.80564409388921]
[52.2457, 0, 0, 0] [21.8056, 0, 0, 0]
关于c++ - meanStdDev函数中的参数,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/30523087/