我需要在foreach循环中传递带有公共索引键的两个或多个输入,以一次更新多个mysql行。
前端:
<table>
<thead>
<tr>
<th>ID</th>
<th>Column 1</th>
<th>Column 2</th>
</tr>
</thead>
<tbody>
<form method="post" action="process.php">
<?php
$stmt = $mysqli->prepare("SELECT id,column1,column2 FROM table");
$stmt->execute();
$stmt->store_result();
$stmt->bind_result($id,$column1,$column2);
while ($stmt->fetch()) {
?>
<tr>
<td><?php echo $id ?></td>
<!-- Here User will input values for the below two fields in all the rows -->
<td><input type="text" name="column1[<?php echo $id; ?>]"/></td>
<td><input type="text" name="column2[<?php echo $id; ?>]"/></td>
</tr>
<?php } ?>
<input type="submit" name="submit" value="Update all">
</form>
</tbody>
</table>
后端:
<?php
if(isset($_POST['submit'])){
foreach($_POST['column1'],$_POST['column2'] as $key=>$value,$value1){ //column1 and column2 have common $id in each row
$stmt = $mysqli->prepare("UPDATE table SET column1 = ?, column2 = ? WHERE id = ?");
$stmt->bind_param('ssi',$value,$value1,$key);
$stmt->execute();
}
if ($stmt->execute()) {
echo "Done!";
exit();
}
}
?>
在此,每一行的“ column1”和“ column2”之间共有索引键(id)。所有行都有唯一的ID。
我需要在foreach循环中使用公共索引键传递“ column1”和“ column2”的值。这样我就可以在单个查询中更新所有行中的数据库表列“ column1”和“ column2”。
您的所有帮助将不胜感激。
最佳答案
<?php
foreach (array_keys($_POST['column1']) as $key) {
$value = $_POST['column1'][$key];
$value1 = $_POST['column2'][$key];
$stmt = $mysqli->prepare("UPDATE table SET column1 = ?, column2 = ? WHERE id = ?");
$stmt->bind_param('ssi',$value,$value1,$key);
$stmt->execute();
}
关于php - 如何在foreach循环中使用公共(public)索引键传递多个值?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/43332880/