我有一个异类数组,看起来是这样的:
let array: [Any] = [
[1, 2, nil],
3
]
我想把它展平成一个数组[1,2,3]。我该怎么做?我可以用什么方式使用
compactMap { $0 }
吗? 最佳答案
extension Collection {
func flatMapped<T>(with type: T.Type? = nil) -> [T] {
return flatMap { ($0 as? [Any])?.flatMapped() ?? ($0 as? T).map { [$0] } ?? [] }
}
}
let array: [Any] = [[1, 2, nil],3]
// Use the syntax of your choice
let flattened1: [Int] = array.flatMapped() // [1, 2, 3]
let flattened2 = array.flatMapped(with: Int.self) // [1, 2, 3]
let flattened3 = array.flatMapped() as [Int] // [1, 2, 3]
关于swift - 如何扁平化异构值的可选数组,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/52166674/