xcode - 与截图和文本共享URL

我有一个非常快速的初学者问题：如何让此函数也共享URL？我始终遵循所有内容，并认为我做对了，但似乎不太奏效……非常感谢！

func takeSnapshot(view: UIView) {
    let bounds = UIScreen.mainScreen().bounds
    UIGraphicsBeginImageContextWithOptions(bounds.size, true, 0.0)
    self.view.drawViewHierarchyInRect(bounds, afterScreenUpdates: false)
    let image = UIGraphicsGetImageFromCurrentImageContext()
    UIGraphicsEndImageContext()
    let text = "Text to be shared... #Hashtag"
    let activityViewController = UIActivityViewController(activityItems: [image, text], applicationActivities: nil)
    self.presentViewController(activityViewController, animated: true, completion: nil)

最佳答案

只需添加一个NSURL：

let bounds = UIScreen.mainScreen().bounds
UIGraphicsBeginImageContextWithOptions(bounds.size, true, 0.0)
self.view.drawViewHierarchyInRect(bounds, afterScreenUpdates: false)
let image = UIGraphicsGetImageFromCurrentImageContext()
UIGraphicsEndImageContext()
let text = "Text to be shared... #Hashtag"
let URL = NSURL(string: "http://stackoverflow.com/")!

let activityViewController = UIActivityViewController(activityItems: [image, text, URL], applicationActivities: nil)
self.presentViewController(activityViewController, animated: true, completion: nil)

关于xcode - 与截图和文本共享URL，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/32216505/