当我尝试测试我的应用程序时,突然我遇到意外的异常,而我还不知道原因,请帮助我找到错误。
(错误是:could not find class "com.example.MyPagerAdapter
“)
这是我第二次活动的代码
注意:此应用程序只是测试滑动,我只是从类MyPagerAdapter
定义了一个适配器,然后定义了这样的ViewPager
ViewPager myPager = (ViewPager) findViewById(R.id.home_pannels_pager);
然后设置适配器,当前项目= 0
package com.example.tstswipe;
import android.content.Context;
import android.content.Intent;
import android.os.Parcelable;
import android.support.v4.view.PagerAdapter;
import android.support.v4.view.ViewPager;
import android.view.View;
import android.webkit.WebView.FindListener;
import android.widget.Button;
import android.widget.LinearLayout;
import android.widget.TextView;
public class MyPagerAdapter extends PagerAdapter {
// State number of pages
public int getCount() {
return 5;
}
// Set each screen's content
public Object instantiateItem(View container, int position) {
Context context = container.getContext();
LinearLayout layout = new LinearLayout(context);
// Add elements
TextView textItem = new TextView(context);
Button buttonItem = new Button(context);
buttonItem.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Intent intent = new Intent("com.phone");
// myFancyMethod(v);
}
});
switch (position) {
case 0:
textItem.setText("First Screen");
break;
case 1:
textItem.setText("Second Screen");
break;
case 2:
textItem.setText("Third Screen");
break;
case 3:
textItem.setText("Fourth Screen");
break;
case 4:
textItem.setText("Fifth Screen");
break;
}
layout.addView(textItem);
((ViewPager) container).addView(layout, 0); // This is the line I added
return layout;
}
public void destroyItem(View arg0, int arg1, Object arg2) {
((ViewPager) arg0).removeView((View) arg2);
}
public boolean isViewFromObject(View arg0, Object arg1) {
return arg0 == ((View) arg1);
}
public Parcelable saveState() {
return null;
}
}
最佳答案
您指出错误是could not find class "com.example.MyPagerAdapter"
,但是发布的类的标准名称是com.example.tstswipe.MyPagerAdapter
。
关于java - 运行时异常:找不到类,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/17784629/