我的表格编辑:
$params = array (
'host' => 'localhost',
'username' => 'root',
'password' => '',
'dbname' => 'my_address_book'
);
$db = Zend_Db::factory('PDO_MYSQL', $params);
$stmt = $db->query('SELECT * FROM user WHERE userName LIKE ?', $name2.'%');
while ($row = $stmt->fetch())
{
$flag1 = 1;
$id = $row['userId'];
echo '<table width="300px">';
echo '
<tr>
<th align="left">Name</th>
<td>:</td>
<td align="left">'.$row["userName"].'</td>
<td><a href ="Edit?id ="'.$id.'">Edit</a></td>
</tr>
';
echo '
<tr>
<th align="left">Address1</th>
<td>:</td>
<td align="left">'.$row["addressLine1"].'</td>
<td><a href="Delete?id="'.$row['userId'].'">Delete</a></td>
</tr>
';
echo '</table>';
}flag1 = 1;
$id = $row['userId'];
echo '<table width="300px">';
echo '
<tr>
<th align="left">Name</th>
<td>:</td>
<td align="left">'.$row["userName"].'</td>
<td><a href ="Edit?id ="'.$id.'">Edit</a></td>
</tr>
';
echo '
<tr>
<th align="left">Address1</th>
<td>:</td>
<td align="left">'.$row["addressLine1"].'</td>
<td><a href ="Delete?id="'.$row['userId'].'">Delete </a></td>
</tr>';
echo '</table>';
在我的EditController中:
if ($this->getRequest()->isPost('$id')){
$form = new Application_Form_Edit1();
$this->view->form = $form;
}
但是它永远不会传递到“ Edit1”形式。
我真的是Zend的新手。我究竟做错了什么?
任何帮助将不胜感激。
最佳答案
尝试使用$this->getRequest()->getParam('id')
代替$this->getRequest()->isPost('id')
。
if (!empty($this->getRequest()->getParam('id'))){
$form = new Application_Form_Edit1();
$this->view->form = $form;
}
旁注:尝试通过MVC标准,并将HTML推送到视图中。
关于php - 如何从URL检索值?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/14934271/