java - 数组超出范围错误Java

我相信您需要看的是第一批代码。其余的代码是在万一我缺少某些东西的情况下。

编辑：确实将第二个j更改为k可解决此问题。我循环了两次j，对于我的数组，值变得太大了。谢谢！

public static void makeMove(){
    char[] path = new char[TicTacToeArray.length];
    int[][] DefensiveOppsArray = new int[TicTacToeArray.length][TicTacToeArray.length];

    for(int i=0; i < DefensiveOppsArray.length; i++){
        for(int j=0; j < DefensiveOppsArray.length; j++){
            DefensiveOppsArray[i][j] = 0;
        }
    }

    for(int i=0; i < DefensiveOppsArray.length; i++){
        for(int j=0; j < DefensiveOppsArray.length; j++){
            //path for straight down
            for(j=0; j < DefensiveOppsArray.length; j++){
                path[j] = TicTacToeArray[i][j];}

                DefensiveOppsArray[i][j]=DefensiveOppsArray[i][j] + 1;


            }
        }
    }

我一直在为井字游戏Java游戏进行这项工作，但一直卡在“线程“主”中的异常” java.lang.ArrayIndexOutofBoundsException：3.此错误来自行DefensiveOppsArray[i][j]=DefensiveOppsArray[i][j] + 1;。这必须表示我不知何故未正确定义DefensiveOppsArray的大小，我在做什么错？

TicTacToeArray继承自UserTicTacToe。测试课程很简单

public class Test3{

public static void main(String[] args){
    IntelligentTicTacToe2.promptUserTTT();
    }
}

我需要创建一个与TicTacToeArray长度相同的DefenceOppsArray，以便可以操纵数字，从而确定最佳移动方式。不幸的是，我在简单地在DefenceOppsArray中创建和处理数字的过程很费劲。

public class IntelligentTicTacToe2 extends UserTicTacToe{

public static void promptUserTTT(){

    //read the input size
    System.out.print("Enter TicTacToe Array Size: ");
    int size = UserInput.readInt();
    System.out.println("");

    //start the game
    UserTicTacToe.startTTT(size);

    //keep track of consecutive errors
    int consecutiveErrors = 0;

    //display the initial game board
    UserTicTacToe.displayTTT();

    //let the user keep playing forever if they want to
    while(true){
        //get the input symbol from the user
        System.out.print("Enter Symbol (X or O): ");
        String symbol = UserInput.readString();
        System.out.println("");
        //hopefully the string is just one character - if not get just
        //the first character
        char sym = '*';
        if(symbol.length() > 0){
            sym = symbol.charAt(0);
        }

        //if the symbol was a Q, then quit
        if(sym == 'Q'){
            break ;
        }

        //get the row and column
        System.out.print("Enter Row to Place Symbol: ");
        int row = UserInput.readInt();
        System.out.println("");
        System.out.print("Enter Col to Place Symbol: ");
        int col = UserInput.readInt();
        System.out.println("");

        //update the game board and see if input was valid
        boolean inputValid = UserTicTacToe.updateTTT(sym,row,col);

        //re-display the game board if input was accepted
        if(inputValid){
            UserTicTacToe.scoreTTT();
            UserTicTacToe.displayTTT();
            consecutiveErrors = 0;
        }
        //if input was rejected, print a message, increment error count,
        //and quit if we are on the 5th error
        else{
            System.out.println("Invalid Input!");
            if(consecutiveErrors >= 4){
                break ;
            }
            consecutiveErrors++;
        }
        makeMove();



    }
}

最佳答案

问题是您在嵌套循环中两次使用j作为计数器

这是出问题的地方：

for(int i=0; i < DefensiveOppsArray.length; i++){
    for(int j=0; j < DefensiveOppsArray.length; j++){
        //path for straight down
        for(j=0; j < DefensiveOppsArray.length; j++){ // << here you use j again as counter
            path[j] = TicTacToeArray[i][j];
            DefensiveOppsArray[i][j]=DefensiveOppsArray[i][j] + 1;
        }
     }
}

也许您编码了一个循环太多？