c++ - C++中的sqlite3创建语句和外键

我正在尝试在c ++中使用sqlite3 create语句和外键，并提出了4个要求。

1) a employer can create a job position
2) a employer can view the form reject or shortlist the applicant for interview
3) a applicant may apply for a job position
4) a applicant must fill up their details and submit the form if they are keen to apply for a position

这是我写的

雇主表

/*SQL statement for employer table*/
 char *sql;
 sql = "CREATE TABLE EMPLOYER("  \
     "ID INT PRIMARY KEY     NOT NULL," \
     "NAME           TEXT    NOT NULL," \
     "ROLE           TEXT    NOT NULL );";

工作表

/*SQL statement for jobposition table */
char *sql;
sql = "CREATE TABLE JOBPOSITION("  \
     "ID INT PRIMARY KEY     NOT NULL," \
     "JOBPOSITION    TEXT    NOT NULL," \
     "OUTCOME        TEXT    NOT NULL );";

表格表

/*SQL statement for form table*/
char *sql;
sql = "CREATE TABLE FORM ("  \
      "ID INT PRIMARY KEY     NOT NULL," \
     "FOREIGN KEY (ID) REFERENCES APPLICANT(ID)",
     "FOREIGN KEY (ID) REFERENCES JOBPOSITION(ID)",
      FOREIGN KEY (ID) REFERENCES EMPLOYER(ID)" );";

申请人表

 /*SQL statement for applicant table*/
 char *sql;
 sql = "CREATE TABLE APPLICANT ("  \
     "ID INT PRIMARY KEY     NOT NULL," \
     "APPLICANT_NAME    TEXT    NOT NULL," \
     "APPLICANT_ADDRESS    TEXT    NOT NULL," );";

我真的不确定这是否正确，因为我刚开始学习数据库并需要一些帮助。

最佳答案

我不知道您所说的“正确”是什么意思，所以我将向您展示我将如何做：

CREATE TABLE users (
    id            INT     NOT NULL PRIMARY_KEY AUTO_INCREMENT,
    name          TEXT    NOT NULL,
    address       TEXT    NOT NULL,
    role          TEXT    NOT NULL,    /* employer, applicant etc. */
);

CREATE TABLE job_positions (
    id             INT    NOT NULL PRIMARY_KEY AUTO_INCREMENT,
    creator_id     INT    NOT NULL FOREIGN_KEY REFERENCES users(id),
    description    TEXT   NOT NULL,
    outcome        TEXT   NOT NULL,
);

CREATE TABLE forms (
    id            INT    NOT NULL PRIMARY_KEY AUTO_INCREMENT,
    position_id   INT    NOT NULL FOREIGN_KEY REFERENCES job_positions(id)
    creator_id    INT    NOT NULL FOREIGN_KEY REFERENCES users(id)
);

通过这种方式，用户与job_positions和表格具有1-N关系；和job_positions与表单具有1-N关系。换句话说，job_positions属于用户；和表格属于用户和职位。