我试图从文件系统上的路径获取一个类,并从中获取字节。我尝试了以下操作,但没有成功。现在应该只打印出名称。如果有人对如何做自己的事情有任何想法,请告诉我。甚至比这更容易...
public class Driver {
public static void main(String[] args) throws Exception {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Enter the path of the class: ");
String from = br.readLine();
System.out.print("Enter the path to save the .txt file (with bytes): ");
String to = br.readLine();
Class clazz = getClassFromPath(from);
System.out.println("Loaded <" + clazz.getName() + "> successfully!");
}
public static Class<?> getClassFromPath(String path) {
try {
File file = new File(path);
URL[] urls = {new URL(path)};
URLClassLoader cl = URLClassLoader.newInstance(urls);
if (!file.isDirectory() && file.getName().endsWith(".class")) {
String className = file.getName().substring(0, file.getName().length() - 6);
className = className.replace('/', '.');
Class c = cl.loadClass(className);
return c;
}
for (File f : file.listFiles()) {
if (f.isDirectory() || !f.getName().endsWith(".class")) {
continue;
}
String className = f.getName().substring(0, f.getName().length() - 6);
className = className.replace('/', '.');
Class c = cl.loadClass(className);
return c;
}
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (ClassNotFoundException e) {
e.printStackTrace();
}
return null;
}
}
最佳答案
我很确定您可以尝试以下方法:
InputStream stream = clazz.getClassLoader().getResourceAsStream(classAsPath);
classAsPath是您在方法getClassFromPath上实际执行的操作
然后,您可能希望使用IOUtils.toByteArray()之类的方法,使用Apache Commons-io将InputStream读取为byte []。