本文实例讲述了Java简单实现农夫过河问题。分享给大家供大家参考,具体如下:
一、问题描述
老伯伯要带鱼、狗、猫过河到对岸.,有一条船,只能坐一个人,老伯每次只能带一样动物过河,当老伯不在的时侯狗会咬猫,猫会吃鱼.,请问怎么顺序过河呢?
二、实现代码
package demo; import java.util.ArrayList; import java.util.List; public class CrossRiver { List<String> listThis = new ArrayList<String>(); List<String> listThat = new ArrayList<String>(); /*boolean thisFlag = true; boolean thatFlag = false; */ public CrossRiver() { listThis.add("dog"); listThis.add("fish"); listThis.add("cat"); // listThis.add("people"); } public boolean isSafe(@SuppressWarnings("rawtypes") List list){ if(list.contains("fish")&&list.contains("cat")||list.contains("cat")&&list.contains("dog")){ return false; }else{ return true; } } public void thisTothat(){ String str = listThis.get(0); listThis.remove(str); if(this.isSafe(listThis)){ System.out.println("农夫带着 " + str + " 从此岸到彼岸"); System.out.println("此岸" + listThis + "\b" + "彼岸" + listThat); System.out.println(); listThat.add(str); thatToThis(); }else{ listThis.add(str); thisTothat(); } } public void thatToThis(){ if(listThis.isEmpty()){ System.out.println("此岸" + listThis + "\b" + "彼岸" + listThat); return; } if(isSafe(listThat)){ System.out.println("农夫从彼岸到此岸"); System.out.println("此岸" + listThis + "\b" + "彼岸" + listThat); System.out.println(); thisTothat(); }else{ String str = listThat.get(0); listThat.remove(0); if(isSafe(listThat)){ System.out.println("农夫带着 " + str + " 从彼岸到此岸"); System.out.println("此岸" + listThis + "\b" + "彼岸" + listThat); System.out.println(); listThis.add(str); thisTothat(); }else{ listThat.add(str); thatToThis(); } } } public static void main(String[] args){ System.out.println("脚本之家测试结果:"); System.out.println(); new CrossRiver().thisTothat(); } }
运行结果:
更多关于java算法相关内容感兴趣的读者可查看本站专题:《Java数据结构与算法教程》、《Java操作DOM节点技巧总结》、《Java文件与目录操作技巧汇总》和《Java缓存操作技巧汇总》
希望本文所述对大家java程序设计有所帮助。