我有两个具有以下结构的类之间的@OneToOne关系:
用户:
@Getter
@Setter
@NoArgsConstructor
@Entity
public class User implements Serializable {
@Id
private Integer id;
private String login;
private String password;
private String name;
private String address;
private Boolean active;
@OneToOne(fetch = FetchType.LAZY)
@JoinColumns( {@JoinColumn(name = "userDetailId", referencedColumnName="id", insertable=false, updatable=false),
@JoinColumn(name = "address", referencedColumnName="location", insertable=false, updatable=false)} )
private UserDetail userDetail;
}
用户详细信息:
@Getter
@Setter
@NoArgsConstructor
@Entity
public class UserDetail implements Serializable {
@Id
private Integer id;
private String location;
}
在我的userRepository中,我使用entityGraph在userDetail的查询中获得左连接
@Repository
public interface UserRepository extends JpaRepository<User, Integer> {
@EntityGraph(attributePaths = {"userDetail"})
List<User> findAll();
}
当我调用findAll()时,我希望有一个左联接查询,因此休眠将使用左联接进行查询,并对用户表中的每一行进行一次user_detail查询,如下所示:
Hibernate:
select
user0_.id as id1_0_0_,
userdetail1_.id as id1_1_1_,
user0_.active as active2_0_0_,
user0_.address as address3_0_0_,
user0_.login as login4_0_0_,
user0_.name as name5_0_0_,
user0_.password as password6_0_0_,
user0_.user_detail_id as user_det7_0_0_,
userdetail1_.location as location2_1_1_
from
user user0_
left outer join
user_detail userdetail1_
on user0_.user_detail_id=userdetail1_.id
and user0_.address=userdetail1_.location
Hibernate:
select
userdetail0_.id as id1_1_0_,
userdetail0_.location as location2_1_0_
from
user_detail userdetail0_
where
userdetail0_.id=?
and userdetail0_.location=?
如何取消对use_detail的查询?
我尝试过
@Fetch(FetchMode.JOIN)
@LazyToOne(LazyToOneOption.NO_PROXY)
当我使用单个主键@JoinColumn而不是@JoinColumnS时,休眠只用一个左联接进行查询,但我需要多个键。
poc here的链接
谢谢你读我
最佳答案
我会尝试在@OneToOne注释中使用attribut optional = true属性:
@OneToOne(optional=false)
我过去曾解决过这个问题,如果我没记错的话,这对您来说可能是正确的。
关于java - @JoinColumnS涉及以一对一关系获取EAGER,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/60196770/