php - undefined index :第6行上的usersJSON []

我试图通过Android应用程序发布JSON，然后将JSON解码为Array，但得到：未定义索引：第6行上的usersJSON []

//Get JSON posted by Android Application
$json = $_POST["usersJSON"]; // Undefined index

php脚本如下所示：

<?php
include_once './db_functions.php';
//Create Object for DB_Functions clas
$db = new DB_Functions();
//Get JSON posted by Android Application
$json = $_POST["usersJSON"]; // Undefined index
//Remove Slashes
if (get_magic_quotes_gpc()){
$json = stripslashes($json);
}
//Decode JSON into an Array
$data = json_decode($json);
//Util arrays to create response JSON
$a=array();
$b=array();
//Loop through an Array and insert data read from JSON into MySQL DB
for($i=0; $i<count($data) ; $i++)
{
//Store User into MySQL DB
$res = $db->storeUser($data[$i]->userId,$data[$i]->userName);
    //Based on inserttion, create JSON response
    if($res){
        $b["id"] = $data[$i]->userId;
        $b["status"] = 'yes';
        array_push($a,$b);
    }else{
        $b["id"] = $data[$i]->userId;
        $b["status"] = 'no';
        array_push($a,$b);
    }
}
//Post JSON response back to Android Application
echo json_encode($a);
?>

最佳答案

看起来$_POST["usersJSON"]没有设置或为空（您没有该索引的值）

检查您是否在url上发布

usersJSON='yourjsondata'

对于隐藏未定义索引错误，您需要先通过isset()或empty()进行检查

$json = (isset($_POST["usersJSON"])? $_POST["usersJSON"] : '');

或检查是否为空

if(!empty($_POST["usersJSON"]) {
   $json = $_POST["usersJSON"];
 }
 else {
  echo 'getting blank';
 }