我正在阅读here中的代码。我在TreeList.cs中找到了private ITreeModel _model;

namespace Aga.Controls.Tree
{
    public class TreeList: ListView
    {
        #region Properties
        //...
        private ITreeModel _model;
        public ITreeModel Model
        {
            //...
        }
        //...
    }
}


ITreeModel是ITreeModel.cs中的接口:

namespace Aga.Controls.Tree
{
    public interface ITreeModel
    {
        /// <summary>
        /// Get list of children of the specified parent
        /// </summary>
        IEnumerable GetChildren(object parent);

        /// <summary>
        /// returns wheather specified parent has any children or not.
        /// </summary>
        bool HasChildren(object parent);
    }
}


_model是实例化的对象吗?

编辑:

TreeList.cs

namespace Aga.Controls.Tree
{
    public class TreeList: ListView
    {
        #region Properties

        /// <summary>
        /// Internal collection of rows representing visible nodes, actually displayed in the ListView
        /// </summary>
        internal ObservableCollectionAdv<TreeNode> Rows
        {
            get;
            private set;
        }

        private ITreeModel _model;
        public ITreeModel Model
        {
            get { return _model; }
            set
            {
                if (_model != value)
                {
                    _model = value;
                    _root.Children.Clear();
                    Rows.Clear();
                    CreateChildrenNodes(_root);
                }
            }
        }

        private TreeNode _root;
        internal TreeNode Root
        {
            get { return _root; }
        }
        //....
    }
}


}

编辑2:

某处:

public partial class RegistrySample : UserControl
{
    public RegistrySample()
    {
        InitializeComponent();
        _tree.Model = new RegistryModel();
    }
}


class RegistryModel : ITreeModel

最佳答案

当然可以做到这一点,但是基础对象必须实现此接口。所以你可以做类似的事情

ITreeModel _model  = new TreeModel();


哪里

public class TreeModel:ITreeModel
{
  ...
}

10-08 14:02