我正在尝试编辑文件格式，对不，它看起来像这样：
>集群0
L07510
>集群1
AF480591
AY457083
>集群2
M88154
>集群3
CP000924
L09161
>集群4
AY742307
>集群5
L09163
L09162
>集群6
AF321086
>集群7
DQ666175
>集群8
DQ288691
我想在python中写一些东西，将通过每行，停在说“ Cluster x”（x为数字）的行，然后将该数字添加到其后的任何行中。然后，当到达新的“集群x”时，它将以新的x值再次开始。
所以它看起来像这样：
>集群0
0 L07510
>集群1
1个AF480591
1 AY457083
>集群2
2 M88154
>集群3
3个CP000924
3 L09161
>集群4
4 AY742307
>集群5
5 L09163
5 L09162
>集群6
6个AF321086
>集群7
7 DQ666175
>集群8
8 DQ288691
我当时想我可以使用regex，搜索">Cluster x"（正则表达式看起来像这样吗？我只是不确定如何实际写这个。任何帮助将不胜感激！
最佳答案
经过测试
# If you're on a POSIX compliant system, and this script is marked as
# executable, the following line will make this file be automatically
# run by the Python interpreter rather than interpreted as a shell script
#!/usr/bin/env python
# We need the sys module to read arguments from the terminal
import sys
# Open the input file, default mode is 'r', readonly, which is a safe default
infile = open(sys.argv[1])
# Prepare a variable for the cluster number to be used within the loop
cluster = ''
# loop through all lines in the file, but first set up a list comprehension
# that strips the newline character off the line for each line that is read
for line in (line.strip() for line in infile):
if line.startswith('>'):
# string.split() splits on whitespace by default
# we want the cluster number at index 1
cluster = line.split()[1]
# output this line to stdout unmodified
print line
else:
# output any other line modified by adding the cluster number
print cluster + ' ' + line
用法
$ python cluster_format.py input.txt > output.txt