假设有一个名字向量:

(def noms ["Tim" "Joseph" "Steven" "Michael"])


如何从奇数索引中获取名称?

更新:
实际上,我试图在Clojure中重写此Rust代码:

fn main() {
    let nums = [1, 2];
    let noms = ["Tim", "Eston", "Aaron", "Ben"];

    let mut odds = nums.iter().map(|&x| x * 2 - 1);

    for num in odds {
        spawn(proc() {
            println!("{:s} says hello from a lightweight thread!", noms[num]);
        });
    }
}


有惯用的方法吗?

编辑:
这是与上述Rust代码几乎相同的Clojure代码:

(def  noms ["Tim", "Eston", "Aaron", "Ben"])
(doseq [i (take-nth 2 (rest noms))]
    (println i "says hello from a lightweight thread!"))


新的问题是:如何编写“轻量级”线程(或Clojure术语中的等效项)?

最佳答案

您可以使用take-nth

(take-nth 2 (rest ["Tim" "Joseph" "Steven" "Michael"]))

10-08 12:45