我正在使用POCO(v 1.4.6p4)日志记录框架,但是在格式化字符串时遇到一些问题:

int MyClass::MyMethod(unsigned short number) {
  Logger::get("MyLog").information(Poco::format("Log a number [%u]", number));
}

在这里我得到:
Log a number [ERRFMT]

然后抛出Poco::BadCastException。
深入研究源代码,我注意到该异常被抛出到Any类中:
template <typename ValueType>
ValueType AnyCast(const Any& operand)
  /// AnyCast operator used to extract a copy of the ValueType from an const Any&.
  ///
  /// Example Usage:
  ///     MyType tmp = AnyCast<MyType>(anAny).
  /// Will throw a BadCastException if the cast fails.
  /// Dont use an AnyCast in combination with references, i.e. MyType& tmp = ... or const MyType& = ...
  /// Some compilers will accept this code although a copy is returned. Use the RefAnyCast in
  /// these cases.
{
    ValueType* result = AnyCast<ValueType>(const_cast<Any*>(&operand));
    if (!result) throw BadCastException("Failed to convert between const Any types");
    return *result;
}

有人可以告诉我我错了吗?

最佳答案

您必须添加modifier(h)来实现无符号缩写:

Poco::format("Log a number [%hu]", number)

这种烦恼来自任何人从它那里提取值的严格性-您必须要求确切的类型,否则,您只能获得异常或空指针。

10-08 12:44