haskell - 我无法将基于GADT的玩具动态类型与参数类型一起使用

因此，为了帮助我理解一些更高级的Haskell/GHC功能和概念，我决定采用基于GADT的有效类型的动态类型数据实现，并将其扩展为参数类型。 (对于这个示例的长度，我深表歉意。)

{-# LANGUAGE GADTs #-}

module Dyn ( Dynamic(..),
             toDynamic,
             fromDynamic
           ) where

import Control.Applicative

----------------------------------------------------------------
----------------------------------------------------------------
--
-- Equality proofs
--

-- | The type of equality proofs.
data Equal a b where
    Reflexivity :: Equal a a
    -- | Inductive case for parametric types
    Induction   :: Equal a b -> Equal (f a) (f b)

instance Show (Equal a b) where
    show Reflexivity = "Reflexivity"
    show (Induction proof) = "Induction (" ++ show proof ++ ")"

----------------------------------------------------------------
----------------------------------------------------------------
--
-- Type representations
--

-- | Type representations.  If @x :: TypeRep a@, then @x@ is a singleton
-- value that stands in for type @a@.
data TypeRep a where
    Integer :: TypeRep Integer
    Char :: TypeRep Char
    Maybe :: TypeRep a -> TypeRep (Maybe a)
    List :: TypeRep a -> TypeRep [a]

-- | Typeclass for types that have a TypeRep
class Representable a where
    typeRep :: TypeRep a

instance Representable Integer where typeRep = Integer
instance Representable Char where typeRep = Char

instance Representable a => Representable (Maybe a) where
    typeRep = Maybe typeRep

instance Representable a => Representable [a] where
    typeRep = List typeRep


-- | Match two types and return @Just@ an equality proof if they are
-- equal, @Nothing@ if they are not.
matchTypes :: TypeRep a -> TypeRep b -> Maybe (Equal a b)
matchTypes Integer Integer = Just Reflexivity
matchTypes Char Char = Just Reflexivity
matchTypes (List a) (List b) = Induction <$> (matchTypes a b)
matchTypes (Maybe a) (Maybe b) = Induction <$> (matchTypes a b)
matchTypes _ _ = Nothing


instance Show (TypeRep a) where
    show Integer = "Integer"
    show Char = "Char"
    show (List a) = "[" ++ show a ++ "]"
    show (Maybe a) = "Maybe (" ++ show a ++ ")"


----------------------------------------------------------------
----------------------------------------------------------------
--
-- Dynamic data
--

data Dynamic where
    Dyn :: TypeRep a -> a -> Dynamic

instance Show Dynamic where
    show (Dyn typ val) = "Dyn " ++ show typ

-- | Inject a value of a @Representable@ type into @Dynamic@.
toDynamic :: Representable a => a -> Dynamic
toDynamic = Dyn typeRep

-- | Cast a @Dynamic@ into a @Representable@ type.
fromDynamic :: Representable a => Dynamic -> Maybe a
fromDynamic = fromDynamic' typeRep

fromDynamic' :: TypeRep a -> Dynamic -> Maybe a
fromDynamic' target (Dyn source value) =
    case matchTypes source target of
      Just Reflexivity -> Just value
      Nothing -> Nothing
      -- The following pattern causes compilation to fail.
      Just (Induction _) -> Just value

但是，此编译在最后一行失败(我的行号与示例不匹配):

../src/Dyn.hs:105:34:
    Could not deduce (a2 ~ b)
    from the context (a1 ~ f a2, a ~ f b)
      bound by a pattern with constructor
                 Induction :: forall a b (f :: * -> *).
                              Equal a b -> Equal (f a) (f b),
               in a case alternative
      at ../src/Dyn.hs:105:13-23
      `a2' is a rigid type variable bound by
           a pattern with constructor
             Induction :: forall a b (f :: * -> *).
                          Equal a b -> Equal (f a) (f b),
           in a case alternative
           at ../src/Dyn.hs:105:13
      `b' is a rigid type variable bound by
          a pattern with constructor
            Induction :: forall a b (f :: * -> *).
                         Equal a b -> Equal (f a) (f b),
          in a case alternative
          at ../src/Dyn.hs:105:13
    Expected type: a1
      Actual type: a
    In the first argument of `Just', namely `value'
    In the expression: Just value
    In a case alternative: Just (Induction _) -> Just value

按照我的理解，编译器无法弄清楚Inductive :: Equal a b -> Equal (f a) (f b)，a和b中的非底值必须相等。所以我尝试了Inductive :: Equal a a -> Equal (f a) (f a)，但是在matchTypes :: TypeRep a -> TypeRep b -> Maybe (Equal a b)的定义中也失败了:

../src/Dyn.hs:66:60:
    Could not deduce (a2 ~ a1)
    from the context (a ~ [a1])
      bound by a pattern with constructor
                 List :: forall a. TypeRep a -> TypeRep [a],
               in an equation for `matchTypes'
      at ../src/Dyn.hs:66:13-18
    or from (b ~ [a2])
      bound by a pattern with constructor
                 List :: forall a. TypeRep a -> TypeRep [a],
               in an equation for `matchTypes'
      at ../src/Dyn.hs:66:22-27
      `a2' is a rigid type variable bound by
           a pattern with constructor
             List :: forall a. TypeRep a -> TypeRep [a],
           in an equation for `matchTypes'
           at ../src/Dyn.hs:66:22
      `a1' is a rigid type variable bound by
           a pattern with constructor
             List :: forall a. TypeRep a -> TypeRep [a],
           in an equation for `matchTypes'
           at ../src/Dyn.hs:66:13
    Expected type: TypeRep a1
      Actual type: TypeRep a
    In the second argument of `matchTypes', namely `b'
    In the second argument of `(<$>)', namely `(matchTypes a b)'

更改matchTypes :: TypeRep a -> TypeRep b -> Maybe (Equal a b)的类型以生成matchTypes :: TypeRep a -> TypeRep b -> Maybe (Equal a a)无效(只需将其作为命题读取即可)。 matchTypes :: TypeRep a -> TypeRep a -> Maybe (Equal a a)也不是(另一个琐碎的命题，据我所知，这将要求fromDynamic' to know the的用户使用in the TypeRep的用户使用contained in the Dynamic`)。

所以，我很困惑。关于如何在这里前进的任何指示？

最佳答案

问题在于您的模式的通配符模式会丢失相等信息。如果以这种方式对归纳进行编码，则无法编写涵盖所有情况的(有限)模式集合。解决方案是将归纳从您的数据类型移到定义的值。相关更改如下所示:

data Equal a b where
    Reflexivity :: Equal a a

induction :: Equal a b -> Equal (f a) (f b)
induction Reflexivity = Reflexivity

matchTypes (List a) (List b) = induction <$> matchTypes a b
matchTypes (Maybe a) (Maybe b) = induction <$> matchTypes a b

fromDynamic' :: TypeRep a -> Dynamic -> Maybe a
fromDynamic' target (Dyn source value) =
    case matchTypes source target of
      Just Reflexivity -> Just value
      Nothing -> Nothing

这样，fromDynamic'中的模式是详尽无遗的，但是没有任何丢失信息的通配符。