假设我有一个NSURL
?它是否已经有一个空的查询字符串,如何在query
的NSURL
中添加一个或多个参数?即,有人知道该功能的实现吗?
- (NSURL *)URLByAppendingQueryString:(NSString *)queryString
使它满足此
NSURL+AdditionsSpec.h
文件:#import "NSURL+Additions.h"
#import "Kiwi.h"
SPEC_BEGIN(NSURL_AdditionsSpec)
describe(@"NSURL+Additions", ^{
__block NSURL *aURL;
beforeEach(^{
aURL = [[NSURL alloc] initWithString:@"http://www.example.com"];
aURLWithQuery = [[NSURL alloc] initWithString:@"http://www.example.com?key=value"];
});
afterEach(^{
[aURL release];
[aURLWithQuery release];
});
describe(@"-URLByAppendingQueryString:", ^{
it(@"adds to plain URL", ^{
[[[[aURL URLByAppendingQueryString:@"key=value&key2=value2"] query] should]
equal:@"key=value&key2=value2"];
});
it(@"appends to the existing query sting", ^{
[[[[aURLWithQuery URLByAppendingQueryString:@"key2=value2&key3=value3"] query] should]
equal:@"key=value&key2=value2&key3=value3"];
});
});
});
SPEC_END
最佳答案
从 iOS 7 开始,您可以使用 NSURLComponents ,它非常易于使用。看一下这些例子:
例子1
NSString *urlString = @"https://mail.google.com/mail/u/0/?shva=1#inbox";
NSURLComponents *components = [[NSURLComponents alloc] initWithString:urlString];
NSLog(@"%@ - %@ - %@ - %@", components.scheme, components.host, components.query, components.fragment);
例子2
NSString *urlString = @"https://mail.google.com/mail/u/0/?shva=1#inbox";
NSURLComponents *components = [[NSURLComponents alloc] initWithString:urlString];
if (components) {
//good URL
} else {
//bad URL
}
例子3
NSURLComponents *components = [NSURLComponents new];
[components setScheme:@"https"];
[components setHost:@"mail.google.com"];
[components setQuery:@"shva=1"];
[components setFragment:@"inbox"];
[components setPath:@"/mail/u/0/"];
[self.webview loadRequest:[[NSURLRequest alloc] initWithURL:[components URL]]];
但是您可以使用NSURLComponents做很多其他事情,看看Apple文档或以下链接上的NSURLComponents类引用:http://nshipster.com/nsurl/
关于objective-c - Objective-C:如何向NSURL添加查询参数?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/6309698/