ios - 尝试使用轻击手势识别器打开网址时，获取线程1:发出信号警告

我正在尝试使用点击手势识别器来在点击图像时打开URL。
代码构建成功，但是当我尝试点击图像时，它终止并显示


  以NSException（lldb）类型的未捕获异常终止


在控制台中。控制台也会显示


  [Hello.ViewController clickToOpen]：无法识别的选择器已发送到实例。


还有一个


  线程1：信号SIGABRT


在行中


  AppDelegate.swift中的类AppDelegate：UIResponder，UIApplicationDelegate {“。


ViewController代码如下：

//
//  ViewController.swift
//  Hello
//

import UIKit

class ViewController: UIViewController, UITextFieldDelegate {

//MARK: Outlets
@IBOutlet weak var nameTextField: UITextField!
@IBOutlet weak var helloName: UILabel!
@IBOutlet weak var imageToTap: UIImageView!

override func viewDidLoad() {
    super.viewDidLoad()

    nameTextField.delegate = self

    let tapGestureRecognizer = UITapGestureRecognizer(target: self, action: Selector(("clickToOpen")))
    self.imageToTap.addGestureRecognizer(tapGestureRecognizer)
    self.imageToTap.isUserInteractionEnabled = true
}

//MARK: UITextFieldDelegate
func textFieldShouldReturn(_ textField: UITextField) -> Bool {
    // Hide the keyboard
    textField.resignFirstResponder()

    return true
}
func textFieldDidEndEditing(_ textField: UITextField) {
    helloName.text = "Hello \(textField.text!)"
    textField.text = ""
}

//MARK: Actions
@IBAction func clearButton(_ sender: UIButton) {
    helloName.text = "Hello"
}
@IBAction func enterButton(_ sender: UIButton) {
    nameTextField.resignFirstResponder()
}
@IBAction func clickToOpen(_ sender: UITapGestureRecognizer) {
     if let url = NSURL(string: "http://www.google.com/") {
        UIApplication.shared.openURL(url as URL)
    }

}

}

最佳答案

替换您的点击手势代码，然后从Swift 3.x开始使用#selector

    let tapGesture = UITapGestureRecognizer.init(target: self, action: #selector(clickToOpen))
    self.view.addGestureRecognizer(tapGesture)