editlistofcustomers.h
QSqlRelationalTableModel *RelationalModel;
TreeModel *CategoriesModel;
QSqlRecord Record;
editlistofcustomers.cpp
EditListOfCustomers :: EditListOfCustomers //构造函数
RelationalModel = new QSqlRelationalTableModel(this, *SupportObj->GetDataBase());
RelationalModel->setTable(SupportObj->GetCustomersTableName());
RelationalModel->setEditStrategy(QSqlTableModel::OnManualSubmit);
RelationalModel->select();
RelationalModel->setHeaderData(1, Qt::Horizontal, QObject::tr("Название/имя покупателя"));
Record = RelationalModel->record();
RelationalModel->setRelation(2, QSqlRelation(SupportObj->GetCategoriesOfCustomersTableName(),
SupportObj->GetCategoriesOfCustomersPattern()[0].GetName(), // ID.
SupportObj->GetCategoriesOfCustomersPattern()[2].GetName())); // Name.
CategoriesModel = new TreeModel(QObject::tr("Категории"),
SupportObj->GetCategoriesOfCustomersTableName(),
SupportObj, this);
//Setup model view delegate.
ui->TV_ListOfCustomers->setModel(RelationalModel);
ui->TV_ListOfCustomers->setItemDelegate(new QSqlRelationalDelegate(ui->TV_ListOfCustomers));
ui->TV_ListOfCustomers->setSelectionBehavior(QAbstractItemView::SelectRows);
ui->TV_ListOfCustomers->setSortingEnabled(true);
ui->TV_CategoryOfCustomer->setModel(CategoriesModel);
SupportObj->GetDataBase()->transaction()
EditListOfCustomers :: AddCustomer
QString customerName = ui->LE_CustomerName->text();
if(!customerName.isEmpty())
{
Record.setValue(SupportObj->GetCustomersPattern()[1].GetName(), QVariant(customerName)); // Name.
int categoryID = CategoriesModel->GetItemID(ui->TV_CategoryOfCustomer->currentIndex());
Record.setValue(SupportObj->GetCustomersPattern()[2].GetName(), QVariant(categoryID)); // Category ID.
Record.setValue(SupportObj->GetCustomersPattern()[3].GetName(), QVariant(ui->LE_CustomerTelephoneNumbers->text())); // Telephone numbers.
Record.setValue(SupportObj->GetCustomersPattern()[4].GetName(), QVariant(ui->LE_CustomerAddress->text())); // Address.
Record.setValue(SupportObj->GetCustomersPattern()[5].GetName(), QVariant(ui->TE_CustomerComment->toPlainText())); // Comment.
RelationalModel->insertRecord(-1, Record);
if(!RelationalModel->submitAll())
{
QMessageBox::warning(this, "CategoriesEditor::CategoriesEditor", SupportObj->GetDataBase()->lastError().text());
}
// Clear fields
ui->LE_CustomerName->clear();
ui->TV_CategoryOfCustomer->setCurrentIndex(QModelIndex());
ui->LE_CustomerTelephoneNumbers->clear();
ui->LE_CustomerAddress->clear();
ui->TE_CustomerComment->clear();
ui->LE_CustomerName->setFocus();
ui->TV_ListOfCustomers->sortByColumn(0, Qt::AscendingOrder);
}
如果注释“ RelationalModel-> setRelation(...)”,则一切正常:事务,添加,删除,提交或回滚。如果取消注释,则没有任何效果,但是一切正常(ID替换为类别名称),但是我无法使用“ insertRecord”插入新行。我尝试this
建议,但未成功。
有什么建议吗?
最佳答案
问题出在列名中。 setRelation
将列名category_of_customer_id
更改为category_of_customers_name_2
。
解决方案使用void setValue(int index, const QVariant &val)
代替void setValue(const QString & name, const QVariant &val)
。
QSqlRecord record = RelationalModel->record();
record.setValue(1, QVariant(customerName)); // Name.
int categoryID = CategoriesModel->GetItemID(ui->TV_CategoryOfCustomer->currentIndex());
record.setValue(2, QVariant(categoryID)); // Category ID.
record.setValue(3, QVariant(ui->LE_CustomerTelephoneNumbers->text())); // Telephone numbers.
record.setValue(4, QVariant(ui->LE_CustomerAddress->text())); // Address.
record.setValue(5, QVariant(ui->TE_CustomerComment->toPlainText())); // Comment.
RelationalModel->insertRecord(-1, record);
if(!RelationalModel->submitAll())
{
QMessageBox::warning(this, "CategoriesEditor::CategoriesEditor", SupportObj->GetDataBase()->lastError().text());
}