我正在使用PySpark,正在寻找一种方法来修改列表中包含的4个rdds。当我显示清单时,我会看到以下内容:

python - 循环PySpark之后的联盟RDD-LMLPHP

因此给定:

for r in repartionned_rdd:

    print r.collect()


给出:

[(u'_guid_NCw7SuFnCh_mFW3SI3qTvBCbqXKD4mtsdJvWE7HNgNg=', (u'f', u'KSJakOd2|KtC9ZF9h'))]
[(u'_guid_OCs2au-sKnxzPE0uRPDP4hg1vvhgpzRAAYjNWRQpKbw=', (u'f', u'KxrylzuA|KpSXJwH2')), (u'_guid_txH15ULaeUDBC4Z_NlEOj2xoYBFa-08imqIBLfYsKps=', (u'f', u'bda54c71-cd1e-4eb7-856c-ba2e6def30c8|6e189e07-807e-41a2-a60a-b07d894a2905')), (u'_guid_ehCT6NyD9l3q3NV9ZroaWVEo3bnDt4tvbU_fMBrEn1g=', (u'm', u'537D69B4-743A-45B9-BED1-A25AA5926F13|2bb3e466-edc5-4302-b102-3bddb1f8c490|aa4760de-104c-4dc3-94c3-336427f89723')), (u'_guid_9F4Ph5GztLN9IlWNgZWKPMCcT4N3Je6-93iM_130F-c=', (u'f', u'KOQqBzhU|KrDt5GC4')), (u'_guid_nPlE_f-zoOHNYiXJSGXWoVryc1U4Bnfxkow3P0mDUFY=', (u'f', u'Kh3tIZR1|Khs0tRsh|K3geBqb_|KBrVNcDX|Jg2uDy8M|529816a3-ee43-4423-961f-8aedaf25d58c')), (u'331d8410d4924e72b0f0585e888c85ce', (u'f', u'1F37807A-CBEA-4B78-85D7-5A97B37B539E'))]
[(u'28b195c271f14a329235c262e7baecbf', (u'm', u'50c41480-a94e-4afa-a732-b6ed7a057239'))]
[(u'c65ac2064bc14116a363125392dcc6f7', (u'f', u'77e4b9b3-83b4-4553-b274-7a16f553cf05')), (u'171f92200d634d62bdc6685bdb7a94e3', (u'f', u'bdf53cb6-695d-4dde-b0c1-d1a34ebea6f7|a09e4074-c22e-48a1-9976-ee2151b5888c|K1Umlb5M|639B02B4-24AD-4069-99A2-C68E8C8F7F06|KjE3wXIr')), (u'_guid_wQZIzeFxciX9CIHUPeWOF2euOIC0jiOsXVXN98_zCh8=', (u'f', u'F0992237-2598-4B13-AA8A-C37D436B901C|C80D1A89-DD84-4734-838F-128F99EBDD20|KthpuVu0')), (u'_guid_ufOcKO48drwr50yJN26NriX5MLYONwmALxWcmly7oqQ=', (u'f', u'KlY10YxX|KyCVx_km'))]


我的目标是向此列表中的每个rdd添加一种新的“列”。该行将为每个rdd包含一个唯一索引。我的代码:

for i, rdd in enumerate(repartionned_rdd):

    new_rdd = rdd.map(lambda x : x + (float(i), ))

    print new_rdd.collect()


这使 :

[(u'_guid_NCw7SuFnCh_mFW3SI3qTvBCbqXKD4mtsdJvWE7HNgNg=',
 (u'f', u'KSJakOd2|KtC9ZF9h'), 0.0)]

[(u'_guid_OCs2au-sKnxzPE0uRPDP4hg1vvhgpzRAAYjNWRQpKbw=',
 (u'f', u'KxrylzuA|KpSXJwH2'), 1.0),
 (u'_guid_txH15ULaeUDBC4Z_NlEOj2xoYBFa-08imqIBLfYsKps=',
 (u'f', u'bda54c71-cd1e-4eb7-856c-ba2e6def30c8|6e189e07-807e-41a2-a60a-b07d894a2905'), 1.0),
 (u'_guid_ehCT6NyD9l3q3NV9ZroaWVEo3bnDt4tvbU_fMBrEn1g=',
 (u'm', u'537D69B4-743A-45B9-BED1-A25AA5926F13|2bb3e466-edc5-4302-b102-3bddb1f8c490|aa4760de-104c-4dc3-94c3-336427f89723'), 1.0),
 (u'_guid_9F4Ph5GztLN9IlWNgZWKPMCcT4N3Je6-93iM_130F-c=',
 (u'f', u'KOQqBzhU|KrDt5GC4'), 1.0),
 (u'_guid_nPlE_f-zoOHNYiXJSGXWoVryc1U4Bnfxkow3P0mDUFY=',
 (u'f', u'Kh3tIZR1|Khs0tRsh|K3geBqb_|KBrVNcDX|Jg2uDy8M|529816a3-ee43-4423-961f-8aedaf25d58c'), 1.0),
 (u'331d8410d4924e72b0f0585e888c85ce',
 (u'f', u'1F37807A-CBEA-4B78-85D7-5A97B37B539E'), 1.0)]

[(u'28b195c271f14a329235c262e7baecbf',
 (u'm', u'50c41480-a94e-4afa-a732-b6ed7a057239'), 2.0)]

[(u'c65ac2064bc14116a363125392dcc6f7',
 (u'f', u'77e4b9b3-83b4-4553-b274-7a16f553cf05'), 3.0),
 (u'171f92200d634d62bdc6685bdb7a94e3',
 (u'f', u'bdf53cb6-695d-4dde-b0c1-d1a34ebea6f7|a09e4074-c22e-48a1-9976-ee2151b5888c|K1Umlb5M|639B02B4-24AD-4069-99A2-C68E8C8F7F06|KjE3wXIr'), 3.0),
 (u'_guid_wQZIzeFxciX9CIHUPeWOF2euOIC0jiOsXVXN98_zCh8=',
 (u'f', u'F0992237-2598-4B13-AA8A-C37D436B901C|C80D1A89-DD84-4734-838F-128F99EBDD20|KthpuVu0'), 3.0),
 (u'_guid_ufOcKO48drwr50yJN26NriX5MLYONwmALxWcmly7oqQ=',
 (u'f', u'KlY10YxX|KyCVx_km'), 3.0)]


因此,new_rdd中的每一行都包含一个新列,具体来说就是rdd的索引(如代码中所述!)

我现在的目标只是将所有这些新rdds放在一个唯一的rdd中。
我尝试了这个:

all_rdds_list =[]

for i, rdd in enumerate(repartionned_rdd):

    new_rdd = rdd.map(lambda x : x + (float(i), ))

    all_rdds_list.append(new_rdd)


但是,当我尝试显示rdds时,我得到了:

for x in all_rdds_list:

    print x.collect()


结果:

[(u'_guid_NCw7SuFnCh_mFW3SI3qTvBCbqXKD4mtsdJvWE7HNgNg=',
 (u'f', u'KSJakOd2|KtC9ZF9h'), 3.0)]

[(u'_guid_OCs2au-sKnxzPE0uRPDP4hg1vvhgpzRAAYjNWRQpKbw=',
 (u'f', u'KxrylzuA|KpSXJwH2'), 3.0),
 (u'_guid_txH15ULaeUDBC4Z_NlEOj2xoYBFa-08imqIBLfYsKps=',
 (u'f', u'bda54c71-cd1e-4eb7-856c-ba2e6def30c8|6e189e07-807e-41a2-a60a-b07d894a2905'), 3.0),
 (u'_guid_ehCT6NyD9l3q3NV9ZroaWVEo3bnDt4tvbU_fMBrEn1g=',
 (u'm', u'537D69B4-743A-45B9-BED1-A25AA5926F13|2bb3e466-edc5-4302-b102-3bddb1f8c490|aa4760de-104c-4dc3-94c3-336427f89723'), 3.0),
 (u'_guid_9F4Ph5GztLN9IlWNgZWKPMCcT4N3Je6-93iM_130F-c=',
 (u'f', u'KOQqBzhU|KrDt5GC4'), 3.0),
 (u'_guid_nPlE_f-zoOHNYiXJSGXWoVryc1U4Bnfxkow3P0mDUFY=',
 (u'f', u'Kh3tIZR1|Khs0tRsh|K3geBqb_|KBrVNcDX|Jg2uDy8M|529816a3-ee43-4423-961f-8aedaf25d58c'), 3.0),
 (u'331d8410d4924e72b0f0585e888c85ce',
 (u'f', u'1F37807A-CBEA-4B78-85D7-5A97B37B539E'), 3.0)]

[(u'28b195c271f14a329235c262e7baecbf',
 (u'm', u'50c41480-a94e-4afa-a732-b6ed7a057239'), 3.0)]

[(u'c65ac2064bc14116a363125392dcc6f7',
 (u'f', u'77e4b9b3-83b4-4553-b274-7a16f553cf05'), 3.0),
 (u'171f92200d634d62bdc6685bdb7a94e3',
 (u'f', u'bdf53cb6-695d-4dde-b0c1-d1a34ebea6f7|a09e4074-c22e-48a1-9976-ee2151b5888c|K1Umlb5M|639B02B4-24AD-4069-99A2-C68E8C8F7F06|KjE3wXIr'), 3.0),
 (u'_guid_wQZIzeFxciX9CIHUPeWOF2euOIC0jiOsXVXN98_zCh8=',
 (u'f', u'F0992237-2598-4B13-AA8A-C37D436B901C|C80D1A89-DD84-4734-838F-128F99EBDD20|KthpuVu0'), 3.0),
 (u'_guid_ufOcKO48drwr50yJN26NriX5MLYONwmALxWcmly7oqQ=',
 (u'f', u'KlY10YxX|KyCVx_km'), 3.0)]


救命 ?谢谢 !

最佳答案

您的方法有两个问题。首先,您使用一个变量,该变量在评估方法分配之前会发生变化。映射调用是转换,因此仅在应用操作(例如collect)时执行。这就是为什么当您在枚举循环中收集时,您会看到正确的附加列,但是在后面的示例中,它为每个映射选择了i的最后一个值。

第二个问题是,如果您尝试将rdds合并在一起,则应使用union函数而不是rdds列表。如果您确实想要rdds列表,则可以用之前的列表替换下面的联合。

full_rdd = None
for i, rdd in enumerate(repartionned_rdd):
    new_rdd = rdd.map(lambda x : x + (float(i),))
    if full_rdd is None:
        full_rdd = new_rdd
    else:
        full_rdd = sc.union([full_rdd, new_rdd])
    # This will force the lazy evaluation to execute now before `i` changes
    full_rdd.count()

关于python - 循环PySpark之后的联盟RDD,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/40533205/

10-13 01:14