我有一个查询,返回的数据是这样的:

releaseid | name | format |
---------------------------
1         | erbr | CD
1         | erbr | DVD
2         | name | CD
3         | test | CD
4         | yo   | CD
4         | yo   | CASETE
5         | hey  | 8 TRACK


请注意,某些releaseid的格式多于1。

在PHP中,我使用准备好的语句来初始化数组,如下所示:

$conn = fn_connect(); // my function to connect to db
$q = 'SELECT ....';
$stmt = $conn->prepare($q);
$stmt->bind_param('i', $recordingid);
$stmt->execute();
$stmt->bind_result($id, $name, $format);
$stmt->store_result();
$num_rows = $stmt->num_rows;

if ( $num_rows > 0 ) {
    $releases = array();

    while ( $stmt->fetch() ) {
        $releases[$id] = array('releaseid'=>$id, 'releasename'=>$name, 'releaseformat'=>$format);
    }
}

$stmt->free_result();
$stmt->close();


如您所见,当我循环时,我按releaseid分组数据,而当releaseid的格式超过1种时,它仅保留最后一种格式:

Array
(
    [1] => Array
        (
            [releaseid] => 1
            [releasename] => erbr
            [releaseformat] => DVD
        )

    [2] => Array
        (
            [releaseid] => 2
            [releasename] => name
            [releaseformat] => CD
        )
...
)


我正在尝试创建一个多维数组,以便我可以保留releaseid的所有格式

我试过使用以下内容,但同样,它保留了最后一种格式

while ( $stmt->fetch() ) {
        $releases[$id] = array('releaseid'=>$id, 'releasename'=>$name, array('format'=>$format));
    }

最佳答案

您需要检查$id中的$releases条目是否已经存在,如果存在,则将新格式值与其现有的releaseformat值合并。像这样:

while ( $stmt->fetch() ) {
    if (isset($releases[$id])) {
        $releases[$id]['releaseformat'][] = $format;
    }
    else {
        $releases[$id] = array('releaseid'=>$id, 'releasename'=>$name, 'releaseformat'=>array($format));
    }
}


这将为您提供如下所示的值:

[1] => Array
    (
        [releaseid] => 1
        [releasename] => erbr
        [releaseformat] => Array
            (
                 [0] => CD
                 [1] => DVD
            )
    )

10-08 08:49