我正在尝试在Scala中实现类似于C#'s ExpandoObject
的类。这是应该如何工作的:
val e = new ExpandoObject
e.name := "Rahul" // This inserts a new field `name` in the object.
println(e.name) // Accessing its value.
到目前为止,这是我尝试过的:
implicit def enrichAny[A](underlying: A) = new EnrichedAny(underlying)
class EnrichedAny[A](underlying: A) {
// ...
def dyn = new Dyn(underlying.asInstanceOf[AnyRef])
}
class Dyn(x: AnyRef) extends Dynamic {
def applyDynamic(message: String)(args: Any*) = {
new Dyn(x.getClass.getMethod(message,
args.map(_.asInstanceOf[AnyRef].getClass) : _*).
invoke(x, args.map(_.asInstanceOf[AnyRef]) : _*))
}
def typed[A] = x.asInstanceOf[A]
override def toString = "Dynamic(" + x + ")"
}
class ExpandoObject extends Dynamic {
private val fields = mutable.Map.empty[String, Dyn]
def applyDynamic(message: String)(args: Any*): Dynamic = {
fields get message match {
case Some(v) => v
case None => new Assigner(fields, message).dyn
}
}
}
class Assigner(fields: mutable.Map[String, Dyn], message: String) {
def :=(value: Any): Unit = {
fields += (message -> value.dyn)
}
}
当我尝试编译此代码时,我得到了
StackOverflowError
。请帮助我完成这项工作。 :) 谢谢。 最佳答案
经过一番游戏后,它开始工作了。但是,该解决方案不是类型安全的(在这种情况下,这无关紧要,因为这个小实用程序的重点是解决类型系统。:-)
trait ExpandoObject extends Dynamic with mutable.Map[String, Any] {
lazy val fields = mutable.Map.empty[String, Any]
def -=(k: String): this.type = { fields -= k; this }
def +=(f: (String, Any)): this.type = { fields += f; this }
def iterator = fields.iterator
def get(k: String): Option[Any] = fields get k
def applyDynamic(message: String)(args: Any*): Any = {
this.getOrElse(message, new Assigner(this, message))
}
}
implicit def anyToassigner(a: Any): Assigner = a match {
case x: Assigner => x
case _ => sys.error("Not an assigner.")
}
class Assigner(ob: ExpandoObject, message: String) {
def :=(value: Any): Unit = ob += (message -> value)
}