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我在整个网站上都看到了这一点,但仍然无法解决我的问题。这是我唯一的错误,我不知道如何解决。我尝试注释掉代码的不同部分,只是为了看看会发生什么,除了错误之外什么也没有。到底是怎么回事?
她也是构建错误
错误C2084:函数'HeroProfile::HeroProfile(void)'已经具有主体
Main.cpp
头文件
和第二个.cpp文件
第二个是
基于我看不到的事实,您可能打算将第二个用作您的类析构函数(在头文件中声明但在cpp文件中未定义),在这种情况下,应将其替换为:
我希望您不要对
想改善这个问题吗?更新问题,以便将其作为on-topic用于堆栈溢出。
6年前关闭。
Improve this question
我在整个网站上都看到了这一点,但仍然无法解决我的问题。这是我唯一的错误,我不知道如何解决。我尝试注释掉代码的不同部分,只是为了看看会发生什么,除了错误之外什么也没有。到底是怎么回事?
她也是构建错误
错误C2084:函数'HeroProfile::HeroProfile(void)'已经具有主体
Main.cpp
#include <iostream>
#include <string>
#include "HeroProfile.h"
using namespace std;
int main()
{
string name;
int race;
double weight;
cout << "Enter your Hero's name:";
cin>> name;
cout << "Enter your Hero's Race (1:Elf 2:Human 3 Dwarf)";
cin >> race;
cout << "Enters your Hero's weight ( in pounds):";
cin >> weight;
HeroProfile Hero_1(name, race, weight);
cout << endl << "hero's Name: " << Hero_1.getName() << endl <<
"Race: " << Hero_1.getRace() << endl <<
"Weight:" << Hero_1.getWeight() << endl;
cout << endl;
cout << "Enter your Hero's Name:";
cin >> name;
cout << "Enter your Race (1:Elf 2:Human 3 Dwarf)";
cin >> race;
cout <<"Enter your Hero's weight (in pounds)";
cin >> weight;
HeroProfile Hero_2(name, race, weight);
Hero_2.setName(name);
Hero_2.setRace(race);
Hero_2.setWeight(weight);
cout << endl << "Hero's Name: " << Hero_2.getName() << endl <<
"Race: " << Hero_2.getRace() << endl << "Weight: " << Hero_2.getWeight() << endl;
return 0;
}
头文件
#include <iostream>
#include <string>
using namespace std;
#ifndef HeroProfiel_H
#define HeroProfile_H
class HeroProfile
{
public:
//default constructor
HeroProfile();
//overlaod constructor
HeroProfile(string, int, double);
//destructor
~HeroProfile();
//Accesor functions
string getName() const;
// get name - returns name of patient
int getRace() const;
// getHeight-returns height of patient
double getWeight() const;
// getWeight- returns weight of patient
//Mutator Functions
void setName(string);
//set name of patient
//@param string - name of patient
void setRace(int);
//setHeight-sets heigh tof patient
//@param int- height iof patient
void setWeight(double);
//setWeight-sets weight of patiend
//@param double-weight of patient
private:
//Memeber variables
string newName;
int newRace;
double newWeight;
};
#endif
和第二个.cpp文件
#include "HeroProfile.h"
eroProfile::HeroProfile() //Default constructor
{
newRace = 0;
newWeight = 0.0;
}
HeroProfile::HeroProfile(string name, int race, double weight) //Overloaded Constructor
{
newName = name;
newRace = race;
newWeight = weight;
}
HeroProfile::HeroProfile()
}
}
//Accessors
string HeroProfile::getName() const
{
return newName;
}
int HeroProfile::getRace() const
{
return newRace;
}
double HeroProfile::getWeight() const
{
return newWeight;
}
//Mutators
void HeroProfile::setName(string name)
{
newName = name;
}
void HeroProfile::setRace(int race)
{
newRace = race;
}
void HeroProfile::setWeight(double weight)
{
newWeight = weight;
}
最佳答案
正如其他人指出的那样,您在第二个cpp文件中为HeroProfile
默认构造函数HeroProfile::HeroProfile()
定义了2个定义:
首先是
HeroProfile::HeroProfile() //Default constructor
{
newRace = 0;
newWeight = 0.0;
}
第二个是
HeroProfile::HeroProfile()
}
}
基于我看不到的事实,您可能打算将第二个用作您的类析构函数(在头文件中声明但在cpp文件中未定义),在这种情况下,应将其替换为:
HeroProfile::~HeroProfile()
}
}
我希望您不要对
HeroProfile::HeroProfile(void)
和HeroProfile::HeroProfile()
是同一件事感到困惑,所以我认为应该指出这一点。10-08 08:15