c++ - gdb:打印sockaddr指针值

目前，我正尝试部署一个用C++编写的网络应用程序，看起来它由于网络问题而陷入无限循环：

[isaev@feck-5 ~]$ sudo strace -p 26252 -f -e trace=network -s 10000
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)

我需要知道应用程序缺少哪个网络连接。
假设我可以用gdb附加到进程，那么如何打印truct sockaddr *指向的0x7f1699ddfb60（man getpeername）变量的值？

最佳答案

您可以“向下转换”并通过执行以下操作取消对指针（或其值）的引用

(gdb) p *((struct sockaddr_in_or_whichever_you_use *) pointer_to_struct_sockaddr)

或

(gdb) p *((struct sockaddr_in_or_whichever_you_use *) 0x7f1699ddfb60)