c# - 将C#类序列化为XML文本的更简单方法

在尝试回答另一个问题时，我正在将C#对象序列化为XML字符串。令人惊讶的是，这很困难。这是我能想到的最短的代码片段:

var yourList = new List<int>() { 1, 2, 3 };
var ms = new MemoryStream();
var xtw = new XmlTextWriter(ms, Encoding.UTF8);
var xs = new XmlSerializer(yourList.GetType());
xs.Serialize(xtw, yourList);
var encoding = new UTF8Encoding();
string xmlEncodedList = encoding.GetString(ms.GetBuffer());

结果还可以:

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfInt
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <int>1</int>
    <int>2</int>
    <int>3</int>
</ArrayOfInt>

但是摘要比我想象的要复杂。我不敢相信您必须了解有关此简单任务的编码和MemoryStream。

有没有更短的方法将对象序列化为XML字符串？

最佳答案

短一点:-)

var yourList = new List<int>() { 1, 2, 3 };
using (var writer = new StringWriter())
{
    new XmlSerializer(yourList.GetType()).Serialize(writer, yourList);
    var xmlEncodedList = writer.GetStringBuilder().ToString();
}

尽管以前的方法存在缺陷，但值得指出。当我们使用StringWriter时，它将生成utf-16 header ，因此它与您的代码不完全相同。要获取utf-8 header ，我们应该使用MemoryStream和XmlWriter，这是另一行代码:

var yourList = new List<int>() { 1, 2, 3 };
using (var stream = new MemoryStream())
{
    using (var writer = XmlWriter.Create(stream))
    {
        new XmlSerializer(yourList.GetType()).Serialize(writer, yourList);
        var xmlEncodedList = Encoding.UTF8.GetString(stream.ToArray());
    }
}