因此，这有点冗长。我正在尝试结束一个票价根据购买日期而变化的程序。我需要Tester.Java从对象中获取信息，并根据票证类型输出适当的价格。我已经在测试器中设置了一组if语句，但是现在对如何完成该程序的工作陷入僵局。我将在下面粘贴我的代码。
测试仪（包含主要方法）：
package tester;
import java.util.Scanner;
public class Tester extends Ticket{
/**
* @param args the command line arguments
*/
public static void main(String[] args){
Scanner db = new Scanner(System.in);
Ticket firstTicket = new Ticket();
System.out.println("The first ticket: "+firstTicket.toString());
int x = 0;
while(x!=2){
if(x==2){
System.out.println("Goodbye.");
}
else{
System.out.println("What type of ticket are you purchasing?");
System.out.println("1.Walk Up");
System.out.println("2.Advance");
System.out.println("3.Student Advance");
int t = db.nextInt();
if(t==1){
}
if(t==2){
}
if(t==3){
}
}
System.out.println("Do you need another ticket?");
x= db.nextInt();
}
}
}
门票（高级舱）：
package tester;
import java.util.Scanner;
public class Ticket {
public int ticket;
public double price;
/**
* holds default values for ticket number and price
*/
public Ticket(){
super();
this.ticket=1;
this.price=15.0;
}
/**
* Stores the values for ticket number and the price, based upon ticket type
* @param ticket
* @param price
*/
public Ticket(int ticket, double price){
this.ticket=ticket;
this.price=price;
}
/**
* returns the value of price
* @return price
*/
public double getPrice(){
return price;
}
@Override
public String toString(){
return "Ticket #" + ticket + " Ticket price: $"+ price;
}
}
门票：
package tester;
/**
*
* @author dylan
*/
public class WalkupTicket extends Ticket{
/**
* holds the price of a walkup ticket 50$
*/
public WalkupTicket(){
this.price=50;
ticket++;
}
}
预售票：
package tester;
import java.util.Scanner;
public class AdvanceTicket extends Ticket {
/**
* stores the values of an advance ticket, depending on how many days before
* the event it is purchased
*/
public AdvanceTicket(){
Scanner db = new Scanner(System.in);
System.out.println("How many days before the event are you purchasing your ticket?");
int days = db.nextInt();
// days before is 10 or less days
if(days >= 10){
price=30;
ticket++;
}
// days before is more than 10
else{
this.price=40;
ticket++;
}
}
}
学生预售票：
package tester;
import java.util.Scanner;
public class StudentAdvanceTicket extends AdvanceTicket{
/**
* stores the values of an advance ticket, depending on how many days before
* the event it is purchased, with student discount.
*/
public StudentAdvanceTicket(){
Scanner db = new Scanner(System.in);
System.out.println("How many days before the event are you purchasing your ticket?");
int days = db.nextInt();
System.out.println("Are you a student?");
System.out.println("1. Yes");
System.out.println("2. No");
int stud = db.nextInt();
// days before is 10 or less days
if(days >= 10 && stud == 1){
price=15;
ticket++;
}
// days before is more than 10
if(days <= 10 && stud == 1){
this.price=20;
ticket++;
}
}
}
我觉得我犯了一个简单的错误，但是我是OOP的新手，所以对此有点麻烦。
最佳答案
您是否应该为所有购买的机票节省总金额，或者一次只节省一张机票？
对于门票，您无需做任何事情。总共$ 50。
对于Advance和StudentAdvance，您将创建一个该类型的新对象，并且您拥有该对象的方式，构造函数将显示菜单，提前多少天，什么不提前。然后，您可以从中获得总计。
至于代码的结构，这并不理想。对象的构造函数中不应包含所有代码。他们应该具有ShowMenu函数，该函数将向用户显示菜单并读取他们的输入。构造函数在大多数情况下应该为空白。
您也不需要三个不同的票证对象。一个票证对象应该能够自己处理所有这一切。票证对象可以显示菜单并根据用户输入处理不同的价格。如果您需要保存总计或其他票证，则可以在main方法上拥有一个票证对象数组。然后，您可以遍历该数组以显示或汇总票证。
希望这可以帮助。
关于java - OOP门票价格计划，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/43811302/