java - 无法正确识别Java字符

我不明白为什么下面的代码：

public Image getLetter(String letterToGet)
{
    System.out.println("é" == "e");

    System.out.println("Received: " + letterToGet);

    if("\u00e9" == letterToGet.toLowerCase()); {
        letterToGet = "SPECIALACCTAIGUESPECIAL";
    }
    if("\u00e8" == letterToGet.toLowerCase()) {
        letterToGet = "SPECIALACCTGRAVESPECIAL";
    }

    System.out.println("searching for " + letterToGet + " in the hashmap");
    return languageMap.get(letterToGet.toLowerCase());
}

可以返回以下输出

Traduction following ArrayList: [e, é, è]
Received: e
searching for SPECIALACCTAIGUESPECIAL in the hashmap
Received: é
searching for SPECIALACCTAIGUESPECIAL in the hashmap
Received: è
searching for SPECIALACCTAIGUESPECIAL in the hashmap

按照此逻辑，为什么此行返回false？

System.out.println("\u00e9" == "e");

最佳答案

输出意外的原因是第一个if之后多余的分号。

目前，您有

if("\u00e9" == letterToGet.toLowerCase()); {
    letterToGet = "SPECIALACCTAIGUESPECIAL";
}

其中letterToGet的分配超出了if的范围，因此无论letterToGet的值如何，它都将运行。