我需要创建一个对象列表,OrganizationRegistration,使用3个实体框架实体(用户、EnrolmentType和OrganizationRegistration)创建:
List<OrganizationEnrolment> organizationEnrolments =
context.Organizations
.SelectMany(x => context.Users)
.SelectMany(x => context.EnrolmentTypes)
.Select(y => new OrganizationEnrolment {
EnrolmentType = enrolmentType
Organization = organization,
User = user
})
我的问题是在拥有selectmany之后,如何从3个joined表中获取enrollmenttype、organization和user?注意以下代码:
EnrolmentType = enrolmentType,
Organization = organization,
User = user
无法工作,因为我没有enrolmenttype、organization和user变量。
最佳答案
可以使用查询语法获取所有这些变量:
from o in context.Organizations
from u in context.Users
from et in context.EnrolmentTypes
select new OrganizationEnrolment {
EnrolmentType = et
Organization = o,
User = u
}
每个局部范围变量都将在select语句中可见。
lambda语法(用ef6检查):
context.Organizations.SelectMany(
o => context.Users.SelectMany(
u => context.EnrolmentTypes.Select(
et => new OrganizationEnrolment {
EnrolmentType = et
Organization = o,
User = u
})
)
)