是否可以使用每个请求的client_credentials或密码授予类型来生成多个有效的访问 token ?

使用以上授权类型生成 token 仅在每个请求当前 token 过期时才提供一个新 token 。

我可以使用密码授予类型来生成刷新 token ,然后生成多个访问 token ,但是这样做会使以前的所有访问 token 无效。

知道如何更改以允许对/oauth/token端点的每个请求生成访问 token ,并确保以前的所有 token 都不会无效吗?

以下是我的oauth服务器的XML配置。

<!-- oauth2 config start-->
  <sec:http pattern="/test/oauth/token" create-session="never"
              authentication-manager-ref="authenticationManager" >
        <sec:intercept-url pattern="/test/oauth/token" access="IS_AUTHENTICATED_FULLY" />
        <sec:anonymous enabled="false" />
        <sec:http-basic entry-point-ref="clientAuthenticationEntryPoint"/>
        <sec:custom-filter ref="clientCredentialsTokenEndpointFilter" before="BASIC_AUTH_FILTER" />
        <sec:access-denied-handler ref="oauthAccessDeniedHandler" />
    </sec:http>


    <bean id="clientCredentialsTokenEndpointFilter"
          class="org.springframework.security.oauth2.provider.client.ClientCredentialsTokenEndpointFilter">
        <property name="authenticationManager" ref="authenticationManager" />
    </bean>

    <sec:authentication-manager alias="authenticationManager">
        <sec:authentication-provider user-service-ref="clientDetailsUserService" />
    </sec:authentication-manager>

    <bean id="clientDetailsUserService"
          class="org.springframework.security.oauth2.provider.client.ClientDetailsUserDetailsService">
        <constructor-arg ref="clientDetails" />
    </bean>

    <bean id="clientDetails" class="org.security.oauth2.ClientDetailsServiceImpl"></bean>

    <bean id="clientAuthenticationEntryPoint"
          class="org.springframework.security.oauth2.provider.error.OAuth2AuthenticationEntryPoint">
        <property name="realmName" value="springsec/client" />
        <property name="typeName" value="Basic" />
    </bean>

    <bean id="oauthAccessDeniedHandler"
          class="org.springframework.security.oauth2.provider.error.OAuth2AccessDeniedHandler"/>

    <oauth:authorization-server
        client-details-service-ref="clientDetails" token-services-ref="tokenServices">
        <oauth:authorization-code />
        <oauth:implicit/>
        <oauth:refresh-token/>
        <oauth:client-credentials />
        <oauth:password authentication-manager-ref="userAuthenticationManager"/>
    </oauth:authorization-server>

    <sec:authentication-manager id="userAuthenticationManager">
        <sec:authentication-provider  ref="customUserAuthenticationProvider">
        </sec:authentication-provider>
    </sec:authentication-manager>

    <bean id="customUserAuthenticationProvider"
          class="org.security.oauth2.CustomUserAuthenticationProvider">
    </bean>

    <bean id="tokenServices"
          class="org.springframework.security.oauth2.provider.token.DefaultTokenServices">
        <property name="tokenStore" ref="tokenStore" />
        <property name="supportRefreshToken" value="true" />
        <property name="accessTokenValiditySeconds" value="300"></property>
        <property name="clientDetailsService" ref="clientDetails" />
    </bean>

    <bean id="tokenStore" class="org.springframework.security.oauth2.provider.token.store.JdbcTokenStore">
        <constructor-arg ref="jdbcTemplate" />
    </bean>

    <bean id="jdbcTemplate"
           class="org.springframework.jdbc.datasource.DriverManagerDataSource">
        <property name="driverClassName" value="com.mysql.jdbc.Driver"/>
        <property name="url" value="jdbc:mysql://localhost:3306/oauthdb"/>
        <property name="username" value="root"/>
        <property name="password" value="password"/>
    </bean>
    <bean id="oauthAuthenticationEntryPoint"
          class="org.springframework.security.oauth2.provider.error.OAuth2AuthenticationEntryPoint">
    </bean>

最佳答案

于21/11/2014更新

当我仔细检查时,我发现InMemoryTokenStore使用OAuth2Authentication的哈希字符串作为服务器Map的键。当我使用相同的用户名,client_id,scope ..时,我得到了相同的key。因此,这可能会导致一些问题。因此,我认为不赞成使用旧方法。以下是我为避免该问题所做的工作。

创建另一个可以计算唯一 key 的AuthenticationKeyGenerator,称为UniqueAuthenticationKeyGenerator

/*
 * Copyright 2006-2011 the original author or authors.
 *
 * Licensed under the Apache License, Version 2.0 (the "License"); you may not use this file except in compliance with
 * the License. You may obtain a copy of the License at
 *
 * http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software distributed under the License is distributed on
 * an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the License for the
 * specific language governing permissions and limitations under the License.
 */

/**
 * Basic key generator taking into account the client id, scope, resource ids and username (principal name) if they
 * exist.
 *
 * @author Dave Syer
 * @author thanh
 */
public class UniqueAuthenticationKeyGenerator implements AuthenticationKeyGenerator {

    private static final String CLIENT_ID = "client_id";

    private static final String SCOPE = "scope";

    private static final String USERNAME = "username";

    private static final String UUID_KEY = "uuid";

    public String extractKey(OAuth2Authentication authentication) {
        Map<String, String> values = new LinkedHashMap<String, String>();
        OAuth2Request authorizationRequest = authentication.getOAuth2Request();
        if (!authentication.isClientOnly()) {
            values.put(USERNAME, authentication.getName());
        }
        values.put(CLIENT_ID, authorizationRequest.getClientId());
        if (authorizationRequest.getScope() != null) {
            values.put(SCOPE, OAuth2Utils.formatParameterList(authorizationRequest.getScope()));
        }
        Map<String, Serializable> extentions = authorizationRequest.getExtensions();
        String uuid = null;
        if (extentions == null) {
            extentions = new HashMap<String, Serializable>(1);
            uuid = UUID.randomUUID().toString();
            extentions.put(UUID_KEY, uuid);
        } else {
            uuid = (String) extentions.get(UUID_KEY);
            if (uuid == null) {
                uuid = UUID.randomUUID().toString();
                extentions.put(UUID_KEY, uuid);
            }
        }
        values.put(UUID_KEY, uuid);

        MessageDigest digest;
        try {
            digest = MessageDigest.getInstance("MD5");
        }
        catch (NoSuchAlgorithmException e) {
            throw new IllegalStateException("MD5 algorithm not available.  Fatal (should be in the JDK).");
        }

        try {
            byte[] bytes = digest.digest(values.toString().getBytes("UTF-8"));
            return String.format("%032x", new BigInteger(1, bytes));
        }
        catch (UnsupportedEncodingException e) {
            throw new IllegalStateException("UTF-8 encoding not available.  Fatal (should be in the JDK).");
        }
    }
}

最后,将它们连接起来
<bean id="tokenStore" class="org.springframework.security.oauth2.provider.token.store.JdbcTokenStore">
    <constructor-arg ref="jdbcTemplate" />
    <property name="authenticationKeyGenerator">
        <bean class="your.package.UniqueAuthenticationKeyGenerator" />
    </property>
</bean>

下面的方式可能会导致一些问题,请参阅更新的答案!!!

您正在使用DefaultTokenServices。尝试使用此代码,并确保重新定义您的`tokenServices`。

包com.thanh.backend.oauth2.core;

导入java.util.Date;
导入java.util.UUID;

导入org.springframework.security.core.AuthenticationException;
导入org.springframework.security.oauth2.common.DefaultExpiringOAuth2RefreshToken;
导入org.springframework.security.oauth2.common.DefaultOAuth2AccessToken;
导入org.springframework.security.oauth2.common.ExpiringOAuth2RefreshToken;
导入org.springframework.security.oauth2.common.OAuth2AccessToken;
导入org.springframework.security.oauth2.common.OAuth2RefreshToken;
导入org.springframework.security.oauth2.provider.OAuth2Authentication;
导入org.springframework.security.oauth2.provider.token.DefaultTokenServices;
导入org.springframework.security.oauth2.provider.token.TokenEnhancer;
导入org.springframework.security.oauth2.provider.token.TokenStore;

/**
* @作者thanh
*/
公共(public)类SimpleTokenService扩展了DefaultTokenServices {

私有(private)TokenStore tokenStore;

私有(private)TokenEnhancer accessTokenEnhancer;

@Override
公开的OAuth2AccessToken createAccessToken(OAuth2Authentication authentication)抛出AuthenticationException {

OAuth2RefreshToken refreshToken = createRefreshToken(authentication);;
OAuth2AccessToken accessToken = createAccessToken(authentication,refreshToken);
tokenStore.storeAccessToken(accessToken,身份验证);
tokenStore.storeRefreshToken(refreshToken,身份验证);
返回accessToken;
}

私有(private)OAuth2AccessToken createAccessToken(OAuth2Authentication身份验证,OAuth2RefreshToken refreshToken){
DefaultOAuth2AccessToken token =新的DefaultOAuth2AccessToken(UUID.randomUUID()。toString());
intvaliditySeconds = getAccessTokenValiditySeconds(authentication.getOAuth2Request());
如果(validitySeconds> 0){
token.setExpiration(new Date(System.currentTimeMillis()+(validitySeconds * 1000L)));;
}
token.setRefreshToken(refreshToken);
token.setScope(authentication.getOAuth2Request()。getScope());

返回accessTokenEnhancer!= null吗? accessTokenEnhancer.enhance( token ,身份验证): token ;
}

私有(private)ExpiringOAuth2RefreshToken createRefreshToken(OAuth2Authentication身份验证){
如果(!isSupportRefreshToken(authentication.getOAuth2Request())){
返回null;
}
intvaliditySeconds = getRefreshTokenValiditySeconds(authentication.getOAuth2Request());
ExpiringOAuth2RefreshToken refreshToken = new DefaultExpiringOAuth2RefreshToken(UUID.randomUUID()。toString(),
新的Date(System.currentTimeMillis()+(validitySeconds * 1000L)));
返回refreshToken;
}

@Override
public void setTokenEnhancer(TokenEnhancer accessTokenEnhancer){
super.setTokenEnhancer(accessTokenEnhancer);
this.accessTokenEnhancer = accessTokenEnhancer;
}

@Override
public void setTokenStore(TokenStore tokenStore){
super.setTokenStore(tokenStore);
this.tokenStore = tokenStore;
}
}

关于java - Spring OAuth2根据对 token 端点的每个请求生成访问 token ,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/27020702/

10-13 02:22