我尝试使用正则表达式从下面的日志中捕获数据组。模式是
<item> : <key> = <value> , <key> = <value>, ..., <key> = <value>
([#\w\d]*?)[\s]*=[\s]*([.\w\d]*)可以捕获组<key>和组<value>但我也想捕获
<item>组，因此我将上述内容分组并使用{n}重复。([\w]*):([\s]*(([#\w\d]*?)[\s]*=[\s]*([.\w\d]*)),*){1,}
20141207,07：15：52,0，>>比率：收银员＃= 30，
值= 2.579，单位=比率，错误= N 20141207,07：15：52,0，>>比率：
收银员＃= 31，值= 4.509，单位=比率，错误= N
20141207,07：15：52,0，>> RATIO：Casher＃= 32，
值= 3.735，单位=比率，错误= N 20141207,07：15：52,0，>>比率：
收银员＃= 33，值= 2.401，单位=比率，错误= N
20141207,07：15：52,0，>>客户：收银员＃= 30，值= 50，单位=计数
20141207,07：15：52,0，>>客户：收银员＃= 31，值= 6，单位=计数
20141207,07：15：52,0，>>客户：收银员＃= 32，值= 88，单位=计数
20141207,07：15：52,0，>>客户：收银员＃= 33，值= 33，单位=计数
显然结果不是预期的。有人可以给我一些提示吗？我最终使用python来翻译代码。谢谢。
最佳答案
(?<=>>)(\w+):|([\w#]+)\s*=\s*(\S+?)(?:,|\s)
试试看，获取捕捉，请看演示。
https://regex101.com/r/fA6wE2/1
NODE EXPLANATION
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(?<= look behind to see if there is:
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>> '>>'
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) end of look-behind
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( group and capture to \1:
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\w+ word characters (a-z, A-Z, 0-9, _) (1 or
more times (matching the most amount
possible))
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) end of \1
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: ':'
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| OR
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( group and capture to \2:
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[\w#]+ any character of: word characters (a-z,
A-Z, 0-9, _), '#' (1 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
) end of \2
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\s* whitespace (\n, \r, \t, \f, and " ") (0 or
more times (matching the most amount
possible))
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= '='
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\s* whitespace (\n, \r, \t, \f, and " ") (0 or
more times (matching the most amount
possible))
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( group and capture to \3:
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\S+? non-whitespace (all but \n, \r, \t, \f,
and " ") (1 or more times (matching the
least amount possible))
--------------------------------------------------------------------------------
) end of \3
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(?: group, but do not capture:
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, ','
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| OR
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\s whitespace (\n, \r, \t, \f, and " ")
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) end of grouping