我想计算一个持续时间,而1天将包括8个小时。
创建新的年表是正确的方法吗?
我确实尝试创建了一个自定义年表,并用类似以下内容的方法覆盖了assemble方法:
int millisPerDay = 1000 * 60 * 60 * 8;
fields.days = new PreciseDurationField(DurationFieldType.days(), millisPerDay);
但是,它没有达到预期的效果。
有什么建议么?
先感谢您
最佳答案
为了回答我自己的问题,下面是一个完整的按时间顺序排列的课程(为时8小时)。
我将其发布在这里,以便对尝试解决类似问题的其他人有所帮助。
import org.joda.time.Chronology;
import org.joda.time.DateTimeZone;
import org.joda.time.DurationFieldType;
import org.joda.time.field.PreciseDurationField;
import org.joda.time.chrono.AssembledChronology;
import org.joda.time.chrono.GregorianChronology;
public final class EightHoursDayChronology extends AssembledChronology {
private static final EightHoursDayChronology INSTANCE_UTC;
static{
INSTANCE_UTC = new EightHoursDayChronology(GregorianChronology.getInstanceUTC());
}
public static EightHoursDayChronology getInstance(){
return INSTANCE_UTC ;
}
private EightHoursDayChronology(Chronology base) {
super(base, null);
}
@Override
protected void assemble(org.joda.time.chrono.AssembledChronology.Fields fields) {
int millisPerDay = 1000 * 60 * 60 * 8 ;
fields.days = new PreciseDurationField(DurationFieldType.days(), millisPerDay)
}
@Override
public Chronology withUTC() {
return INSTANCE_UTC ;
}
@Override
public Chronology withZone(DateTimeZone zone) {
throw new UnsupportedOperationException("Method was not implemented");
}
@Override
public String toString() {
return "EightHoursDayChronology";
}
}