我正在运行Parse云代码,试图在网页上显示我的Twitter提要。这是我在下面的html中使用的javascript。
<script type="application/javascript">
Parse.initialize("my app id", "my javascript id");
enter code herevar Tweets = Parse.Object.extend("Tweets");
var query = new Parse.Query(Tweets);
query.find({
success: function(results) {
// results is an array of your Tweets
console.log(results);
},
error: function(error) {
alert("Error: " + error.code + " " + error.message);
}
});
</script>
这是console.log中的输出
[ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass ,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubSens, ubclass,ParseObjectSubclass,ParseObjectSubClass,ParseObjectSubClass,ParseObjectSubSub,ParseObjectSubSub,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass,ParseObjectSubclass]
它在我的Parse核心仪表板上显示为77条推文,因此云代码可以正常工作。
我如何只以清晰可读的格式显示内容,即twitter头像,消息,时间等?
我尝试按照下面的教程进行操作,但这没有帮助
https://medium.com/@nannerb/tutorial-storing-tweets-in-parse-via-the-twitter-api-9fe2ee092013
最佳答案
那些对象可能具有toString
方法,该方法将返回对象的名称,您可以迭代所有属性以检查它们:
success: function(results) {
for (var i = 0; i < results.length; i++) {
for (var prop in results[i]) {
console.log("Property name -> " . prop);
console.log("Property value -> " . results[i][prop]);
}
}
},
关于javascript - 解析Javascript和Twitter API,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/33044858/