模拟核心版本:1.10.19
powermock版本:1.6.6
我尝试模拟一些静态方法,但输出使我感到困惑。
这是我的代码:
class ClassWithStatics {
public static int getNextInt() {
return getInt() + 1;
}
public static int getInt() {
return 1;
}
public static long getTime() {
return System.currentTimeMillis();
}
}
@RunWith(PowerMockRunner.class)
@PrepareForTest({ClassWithStatics.class, System.class})
public class StubJustOneStatic {
@Test
public void test() {
PowerMockito.mockStatic(ClassWithStatics.class);
Mockito.when(ClassWithStatics.getInt()).thenReturn(0);
PowerMockito.mockStatic(System.class);
Mockito.when(System.currentTimeMillis()).thenReturn(12345L);
System.out.println("Next Int: " + ClassWithStatics.getNextInt());
System.out.println("Int: " + ClassWithStatics.getInt());
System.out.println("Time:" + ClassWithStatics.getTime());
}
}
输出是
Next Int: 0
Int: 0
Time:0
但是,当我使用以下代码时,
ClassWithStatics.getTime()
完全打印我想要的内容。@RunWith(PowerMockRunner.class)
@PrepareForTest({ClassWithStatics.class, System.class})
public class StubJustOneStatic {
@Test
public void test() {
// PowerMockito.mockStatic(ClassWithStatics.class);
// Mockito.when(ClassWithStatics.getInt()).thenReturn(0);
PowerMockito.mockStatic(System.class);
Mockito.when(System.currentTimeMillis()).thenReturn(12345L);
// System.out.println("Next Int: " + ClassWithStatics.getNextInt());
// System.out.println("Int: " + ClassWithStatics.getInt());
System.out.println("Time:" + ClassWithStatics.getTime());
}
}
非常感谢。
最佳答案
您在嘲笑静态类,这意味着,如果未明确定义when().. then()行为,则Mockito将返回默认值(如果为long,则返回0)。
您必须使用间谍程序才能仅模拟某些方法,并让其他方法按实现方式运行:
PowerMockito.spy(ClassWithStatics.class);
Mockito.when(ClassWithStatics.getInt()).thenReturn(5);
现在,当您调用时:
PowerMockito.mockStatic(System.class);
Mockito.when(System.currentTimeMillis()).thenReturn(12345L);
System.out.println("Time:" + ClassWithStatics.getTime());
调用
5
时应获得ClassWithStatics.getInt()
,调用12345L
时应获得ClassWithStatics.getTime()
。