因此,我的应用程序应有意图地捕获图像,然后在其他活动中绘制该图像,但它不起作用。这是我的代码:
主要活动:
b1.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Intent intent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE);
File photo = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_PICTURES), "pic.jpg");
imageUri = Uri.fromFile(photo);
startActivityForResult(intent, 2);
}
});
}
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
if (requestCode == 2) {
Intent k = new Intent(MainActivity.this, FullActivity.class);
startActivity(k);
}
}
第二项活动:
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
Uri selectedImage = imageUri;
iv.setImageBitmap(bp);
}
有人可以帮我看看问题出在哪里。提前致谢。
最佳答案
您需要将Uri
作为字符串与Intent
一起传递给MainActivity
。
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
if (requestCode == 2) {
Intent k = new Intent(MainActivity.this, FullActivity.class);
k.putExtra("uri", imageUri.toString());
startActivity(k);
}
}
然后在
FullActivity
中获取字符串并将其解析为Uri
,然后使用该字符串设置您的ImageView
。@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
...
String uriString = getIntent().getStringExtra("uri");
Uri selectedImage = Uri.parse(uriString);
// you may also need to call imageView.setImageURI(null); here
// or get the bitmap first to use imageView.setImageBitmap();
imageView.setImageURI(selectedImage);
}