我的代码是:
int copyme() {
TCHAR buf[MAX_PATH];
TCHAR szPath[MAX_PATH];
std::array<std::string, 16> locations = { "CSIDL_APPDATA","CSIDL_CDBURN_AREA","CSIDL_COMMON_APPDATA","CSIDL_COMMON_DESKTOPDIRECTORY","CSIDL_COMMON_DOCUMENTS","CSIDL_COMMON_MUSIC","CSIDL_COMMON_PICTURES","CSIDL_COMMON_PROGRAMS","CSIDL_COMMON_STARTMENU","CSIDL_COMMON_STARTUP","CSIDL_COMMON_TEMPLATES","CSIDL_COMMON_VIDEO","CSIDL_DESKTOPDIRECTORY","CSIDL_INTERNET_CACHE","CSIDL_LOCAL_APPDATA","CSIDL_PERSONAL", };
for (auto& location : locations) {
(SHGetFolderPath(NULL,
location | CSIDL_FLAG_CREATE,
NULL,
0,
szPath)
}
我试图用数组中的CSIDL调用
SHGetFolderPath
,但是根据文档:nFolder [输入]
类型:int
CSIDL值,用于标识要检索其路径的文件夹。仅真实文件夹有效。如果指定了虚拟文件夹,此功能将失败。您可以通过组合文件夹的CSIDL和CSIDL_FLAG_CREATE来强制创建文件夹。
因此只能使用
int
。有什么想法我能做什么? 最佳答案
正如SHGetFolderPath
文档明确指出的那样,nFolder
参数是整数,而不是字符串。 CSIDL
值是数字ID,而不是字符串(它们的可读名称在#define
中是shlobj.h
)。
因此,只需将数组从std::string
更改为int
,然后删除CSIDL名称周围的引号字符:
int copyme()
{
TCHAR szPath[MAX_PATH];
std::array<int, 16> locations = {
CSIDL_APPDATA, CSIDL_CDBURN_AREA, CSIDL_COMMON_APPDATA, CSIDL_COMMON_DESKTOPDIRECTORY,
CSIDL_COMMON_DOCUMENTS, CSIDL_COMMON_MUSIC, CSIDL_COMMON_PICTURES, CSIDL_COMMON_PROGRAMS,
CSIDL_COMMON_STARTMENU, CSIDL_COMMON_STARTUP, CSIDL_COMMON_TEMPLATES, CSIDL_COMMON_VIDEO,
CSIDL_DESKTOPDIRECTORY, CSIDL_INTERNET_CACHE, CSIDL_LOCAL_APPDATA, CSIDL_PERSONAL};
for (auto location : locations)
{
SHGetFolderPath(NULL,
location | CSIDL_FLAG_CREATE,
NULL,
0,
szPath);
}