我正在尝试用Java 创建一个矩形,但仅使用 awt包类。
我只能单击两个点,程序必须计算的宽度和高度,并在这两个点之间绘制一个矩形。
以下内容对我不起作用:
package ie.iact.shapes;
import java.awt.Color;
import java.awt.Graphics;
import java.awt.Point;
public class Rect extends Shapes {``
private Point secondPoint;
public Rect(Point f, Point s) {
setFirstPoint(f);
setSecondPoint(s);
}
@Override
public void draw(Graphics g) {
int x1 = firstPoint.x;
int y1 = firstPoint.y;
int x2 = secondPoint.x;
int y2 = secondPoint.y;
int a;
int b;
if (x1 < x2) {
a = x1;
} else {
a = x2;
}
if (y1 < y2) {
b = y1;
} else {
b = y2;
}
int width = secondPoint.x - a;
int hight = secondPoint.y - b;
g.drawRect(getFirstPoint().x, getFirstPoint().y, secondPoint.x, secondPoint.y);
}
public Point getSecondPoint() {
return secondPoint;
}
public void setSecondPoint(Point secondPoint) {
this.secondPoint = secondPoint;
}
}
最佳答案
Rectangle 类已经可以处理您的所有计算:
Rectangle rect= new Rectangle(point1);
rect.add(point2);
g.fillRect(rect.x, rect.y, rect.width, rect.height);