我在初学者的Java课堂上。我已经有3个星期的yahtzee计划了，但仍然无法解决。我需要两次掷5个骰子，以查看是否获得yahtzee（5个骰子相同），我在将骰子保存到第一个骰子中再次滚动时遇到麻烦。我确定有很多事情可以简化（如果转换为switch语句），但是现在我正在关注使这些方法起作用。
我们的老师为我们提供了一个模具课，可用于以下方面
public class Die
{
private final int MAX = 6; // maximum face value
private int faceValue; // current value showing on the die
//-----------------------------------------------------------------
// Constructor: Sets the initial face value.
//-----------------------------------------------------------------
public Die()
{
faceValue = 1;
}
//-----------------------------------------------------------------
// Rolls the die and returns the result.
//-----------------------------------------------------------------
public int roll()
{
faceValue = (int)(Math.random() * MAX) + 1;
return faceValue;
}
//-----------------------------------------------------------------
// Face value mutator.
//-----------------------------------------------------------------
public void setFaceValue(int value)
{
faceValue = value;
}
//-----------------------------------------------------------------
// Face value accessor.
//-----------------------------------------------------------------
public int getVal()
{
return faceValue;
}
//-----------------------------------------------------------------
// Returns a string representation of this die.
//-----------------------------------------------------------------
public String toString()
{
String result = Integer.toString(faceValue);
return result;
}
}
我的Yahtzee代码。
import java.util.*;
public class Yahtzee
{
int a, b, c, d, e;
Die die1 = new Die();
Die die3 = new Die();
Die die4 = new Die();
Die die5 = new Die();
Die die2 = new Die();
Scanner sc = new Scanner(System.in);
ArrayList<Integer> dice2;
int arrayLength;
Die[] dice = new Die[5];
//Constructor
public Yahtzee()
{
for(int i = 0; i < dice.length; i ++)
{
dice[i] = new Die();
}
}
public void roll()
{
for(int i = 0; i < dice.length; i ++)
{
dice[i].roll();
}
}
public void saveDice()
{
dice2 = new ArrayList<Integer>();
for(int i = 0; i < dice.length; i ++)
{
dice[i].getVal();
for(int i2 = 0; i2 < dice.length; i2 ++)
{
if(i != i2)
{
if(dice[i] == dice[i2])
{
dice2.add(dice[i].getVal());
dice2.add(dice[i2].getVal());
a = dice[i].getVal();
if(a == 5)
{
System.out.println("You have " + dice2.size() + "6's");
}
else if(a == 5)
{
System.out.println("You have " + dice2.size() + "5's");
}
else if(a == 4)
{
System.out.println("You have " + dice2.size() + "4's");
}
else if(a == 3)
{
System.out.println("You have " + dice2.size() + "3's");
}
else if(a == 2)
{
System.out.println("You have " + dice2.size() + "2's");
}
else if(a == 1)
{
System.out.println("You have " + dice2.size() + "1's");
}
b = dice2.size();
}
if(dice2.size() == 0)
{
if(a == 6)
{
System.out.println("No dice are the same. We kept 6 because its the largest face value.");
}
else if(a == 5)
{
System.out.println("No dice are the same. We kept 5 because its the largest face value.");
}
else if(a == 4)
{
System.out.println("No dice are the same. We kept 4 because its the largest face value.");
}
else if(a == 3)
{
System.out.println("No dice are the same. We kept 3 because its the largest face value.");
}
else if(a == 2)
{
System.out.println("No dice are the same. We kept 2 because its the largest face value.");
}
else if(a == 1)
{
System.out.println("No dice are the same. We kept 1 because its the largest face value.");
}
}
}
}
}
}
public void rollAgain()
{
arrayLength = dice2.size();
System.out.println(arrayLength);
}
}
我的再次掷骰方法不完整，因为我的保存骰子不起作用。
我的驱动程序如下，但到目前为止在输出中什么都不做，这是我的问题的一部分
public class YahtzeeFinal
{
public static void main(String [] args)
{
Yahtzee yaht = new Yahtzee();
yaht.roll();
yaht.saveDice();
}
}
感谢您的任何建议。
最佳答案
不知道您的代码是否正在运行，或者是否仍在运行，但这就是我想出的。我玩得很开心。您可能会注意到，我试图简化代码的某些部分，所以也许您会发现其中一些有用的方法：）如果您确实使用了其中的某些部分并遇到了问题，请告诉我，我会再看一遍。
import java.util.*;
public class Yahtzee {
ArrayList<Die> savedDice = new ArrayList<Die>();
// Constructor
public Yahtzee() {
}
// renamed method to avoid confusion
public void rollDice(int num) {
Die[] dice = new Die[num];
for (int d = 0; d < dice.length; d++) {
Die nextDie = new Die();
nextDie.roll();
dice[d] = nextDie;
}
saveDice(dice);
}
public void saveDice(Die[] dice) {
// int array will count occurrences of each face value
int[] values = new int[] { 0, 0, 0, 0, 0, 0 };
for (Die d : dice) {
values[d.getVal() - 1]++;
}
int most = -1;
int temp = 0;
for (int j = 0; j < values.length; j++) {
if (values[j] >= temp) {
most = j + 1;
temp = values[j];
}
}
// Thought something like this looked much cleaner than having conditions for each value.
if (temp > 1) {
System.out.println("You have " + temp + " " + most + "'s");
} else {
System.out.println("No dice are the same. We kept " + most
+ " because it's the largest face value.");
}
for (Die d : dice) {
if (d.getVal() == most) {
savedDice.add(d);
}
}
}
}
关于java - 编写yahtzee程序时遇到麻烦，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/34258738/