c++ - 使用GCC而非MSVC进行编译时，使用模板编译错误

表达时:

typedef RDOCalcUnary<RDOValue, (&RDOValue::operator-), OperatorType::OT_ARITHM> RDOCalcUMinus;

gcc显示以下错误:



在Windows下，MSVC编译器可正确编译代码。

有什么问题？我该如何解决？

template <typename ret_type, ret_type (RDOValue::*pOperator)() const, typename OperatorType::Type CalcType>
class RDOCalcUnary: public RDOCalcUnaryBase
{
friend class rdo::Factory<RDOCalcUnary<ret_type, pOperator, CalcType> >;
public:
    enum { calc_type = CalcType };
    typedef ret_type (RDOValue::*value_operator)() const;

    static RDOSrcInfo     getStaticSrcInfo(CREF(RDOSrcInfo::Position) position, CREF(LPRDOCalc) pUnaryCalc);
    static value_operator getOperation    ();

protected:
    RDOCalcUnary(CREF(RDOSrcInfo::Position) position, CREF(LPRDOCalc) pOperation);

private:
    REF(RDOValue) doCalc(CREF(LPRDORuntime) pRuntime);
};

最佳答案

当您执行typedef时，请不要使用方括号:

typedef RDOCalcUnary<RDOValue, &RDOValue::operator-, OperatorType::OT_ARITHM> RDOCalcUMinus;

它对我有用。